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3 years ago

Transform Linear. A2. Q1

Mathematics

1 answer:

belka [17]3 years ago

8 0

That's correct
answer is a
translated 3 units up

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Which of the following scenarios demonstrates an exponential decay? A. A tennis tournament in which after each round, half the p

Sliva [168]

Answer:

A. A tennis tournament in which after each round, half the players are eliminated.

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

George and Paul use a metal alloy that is 18.1% copper to make jewelry. How many ounces of an alloy that is 14% copper must be m

ella [17]

Answer:

Use 49 ounces of the 14% allow and 41 ounces of the 23% alloy.

Step-by-step explanation:

Each ounce of the 14% copper contains 0.14 ounce of pure copper.

Each ounce of the 23% copper contains 0.23 ounce of pure copper.

Each ounce of the 18.1% copper contains 0.181 ounce of pure copper.

Use x ounces of the 14% and y ounces of the 23% to make 90 ounces of 18.1% alloy.

x+y = 90

y = 90-x

0.14x + 0.23y = 0.181·90

0.14x + 0.23(90-x) = 16.29

0.14x + 20.7 - 0.23x = 16.29

-0.09x + 20.7 = 16.29

4.41 = 0.09x

x = 49

y = 90-x = 41

Use 49 ounces of the 14% allow and 41 ounces of the 23% alloy.

7 0

3 years ago

How many times do 14 go into 50

masha68 [24]

=3 times it goes into

4 0

3 years ago

Select the correct answer.

Elina [12.6K]

Answer:

A) 6.86×10⁴

Step-by-step explanation:

You want to write 68600 in scientific notation.

<h3>Expanded form</h3>

The number 68600 can be written in expanded form with exponents as ...

68600 = 6×10⁴ +8×10³ +6×10² +0×10¹ +0×10⁰

The left-most term of this sum tells you the exponent in scientific notation:

68600 = 6.86×10⁴

5 0

1 year ago

Help me find the volume of the composite figure

Butoxors [25]

Answer:

$V = 97.911in^3$

Step-by-step explanation:

Given

Shapes: Cube and Cone

Required

Determine the volume

First we calculate the volume of the cube

$V_1 = l^3$

Where

l = side length = 5.1

$V_1 = 5.1^3$

$V_1 = 132.651$

Next, calculate the volume of the cone using:

$V_2 = \frac{\pi r^2h}{3}$

Where

h = 5.1

$r = \frac{1}{2} * Diameter$

$r = \frac{1}{2} * 5.1$

$r = 2.55$

So, we have:

$V_2 = \frac{\pi r^2h}{3}$

$V_2 = \frac{\pi * 2.55^2 * 5.1}{3}$

$V_2 = \frac{22 * 2.55^2 * 5.1}{7*3}$

$V_2 = \frac{729.5805}{21}$

$V_2 = 34.74$

The volume of the figure is:

$V=V_1 - V_2$

$V_1 = 132.651$

$V = 132.651 - 34.74$

$V = 97.911in^3$

8 0

2 years ago