<span>Equation at the end of step 1 :</span><span> (((x3)•y)-(((3x2•y6)•x)•y))-6y = 0
</span><span>Step 2 :</span><span>Step 3 :</span>Pulling out like terms :
<span> 3.1 </span> Pull out like factors :
<span> -3x3y7 + x3y - 6y</span> = <span> -y • (3x3y6 - x3 + 6)</span>
Trying to factor a multi variable polynomial :
<span> 3.2 </span> Factoring <span> 3x3y6 - x3 + 6</span>
Try to factor this multi-variable trinomial using trial and error<span>
</span>Factorization fails
<span>Equation at the end of step 3 :</span><span> -y • (3x3y6 - x3 + 6) = 0
</span><span>Step 4 :</span>Theory - Roots of a product :
<span> 4.1 </span> A product of several terms equals zero.<span>
</span>When a product of two or more terms equals zero, then at least one of the terms must be zero.<span>
</span>We shall now solve each term = 0 separately<span>
</span>In other words, we are going to solve as many equations as there are terms in the product<span>
</span>Any solution of term = 0 solves product = 0 as well.
Solving a Single Variable Equation :
<span> 4.2 </span> Solve : -y = 0<span>
</span>Multiply both sides of the equation by (-1) : y = 0
Answer: c for the first part
1,6 for the second
nether for the third
Step-by-step explanation:
all on edg
4.b.
Answer: See below.
Step-by-step explanation:
<h2><u>
For the equation f(x) = 2x</u></h2>
3.a. f(6) means use x = 6 in the equation f(x) = 2x
so f(6) would be f(6)= 2(6)
<u>f(6) = 12</u>
3.b. f(-11) = 2(-11)
<u>f(-11) = -22</u>
3.c. f(2.75) = 2(2.75)
<u>f(2.75) = 5.5</u>
3.d. This is turned around. We are told f(x)=20, so what would x need to be for f(x) to be 20? Since f(x) = 2x, we can say 20 = 2x. Therefore x = 10
f(10) = 20
<u>The rest of (3) are solved in the same fasion.h</u>
<u></u>
<h2><u>
For the equation f(x)= 5x+50</u></h2>
4.a. f(7) = 5(7)+50
<u>f(7) = 85</u>
4.b. f(-12)
f(-12) = 5*(-12)+50
<u>f(-12) = -60</u>
<u></u>
Continue in the same fashion for these types of problems.
???/where is what located
Answer:
yjyjytjyjtyjyjtyjtyjyhjyjnfrhjnrthj
Step-by-step explanation:
