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3 years ago

The graph of the function f (x) is shown below. When f(x)=0,x=?

Mathematics

2 answers:

IgorLugansk [536]3 years ago

7 0

Answer:

Step-by-step explanation:

andre [41]3 years ago

4 0

<h2>Answer:</h2>

From the graph of the function f(x) we have:

When f(x)=0 , x= -1.8

<h2>Step-by-step explanation:</h2>

By looking at the graph we observe that the graph first increases in the interval (-∞,-1.2) and then it decreases in the interval (-1.2,0.6) and then again it increases in the interval (0.6,∞).

Hence, the graph of the function is neither strictly increasing nor strictly decreasing in the whole of the real line.

Also, when x=0 the value of the function is: f(x)=5

( Since, the graph passes through the point (0,5) )

Also, when f(x)=0

then x= -1.8

( Since, the graph of the function passes through the point (-1.8,0) )

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If PQR is an equilateral triangle, PQ=18x+1, QR=24x-17, and PR=15x+10, find x and the measure of each side.

Vadim26 [7]

Answer

QR= PQ= PR

18x+1= 24x-17

18x-24x= -17-1

-6x= -18

x= 3

QR= 24(3)-17= 55

PQ= 18(3)+1= 55

PR= 15(3)+10=55

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2 years ago

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A billboard designer has decided that a sign should have 3 ft margins at the top and bottom and 5 ft margins on the left and rig

elixir [45]

Answer:

The width of billboard is "[x]" and the height of billboard is "[y"]. If total area of billboard is $9000 ft^2$ then $9000=xy$

Step-by-step explanation:

• The total width of billboard is [x]. Therefore the width of printed area will be (x-10) by excluding margin of left and right side.

• The total height of billboard is [y]. Therefore the height of printed area will be [(y-6)] by excluding the margin of top and bottom from the total height.

• To find the printed area of billboard calculations are given below:

$& 9000=xy$

$& y=\frac{9000}{x} \\ & A=(x-10)(y-6) \\ & A=xy-6x-10y+60 \\ & A=x\left( \frac{9000}{x} \right)-6x-10\left( \frac{9000}{x} \right)+60 \\ & A=9060-6x-\frac{9000}{x} \\$

On taking the first order derivative of A

$A'=-6+\left( \frac{90000}{{{x}^{2}}} \right)$

$& \left( \frac{90000}{{{x}^{2}}} \right)-6=0 \\ & 6{{x}^{2}}=90000 \\ & x=\sqrt{15000} \\ & y=\frac{9000}{x}=\frac{90000}{\sqrt{15000}}=10\sqrt{150} \\$

• Hence $x=10\sqrt{150}$ and $y=\frac{900}{\sqrt{150}}$

Learn More about Differentiation Here:

brainly.com/question/13012860

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2 years ago

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Semicircles and quarter circles are types of arc lengths. Recall that an arc is simply part of a circle. We learned about the de

attashe74 [19]

The question is incomplete. Here is the complete question.

Semicircles and quarter circles are types of arc lengths. Recall that an arc is simply part of a circle. we learned about the degree measure of an ac, but they also have physical lengths.

a) Determine the arc length to the nearest tenth of an inch.

b) Explain why the following proportion would solve for the length of AC below: $\frac{x}{12\pi } = \frac{130}{360}$

c) Solve the proportion in (b) to find the length of AC to the nearest tenth of an inch.

Note: The image in the attachment shows the arc to solve this question.

Answer: a) 9.4 in

c) x = 13.6 in

Step-by-step explanation:

a) $\frac{arclength}{2\pi.r } = \frac{mAB}{360}$ , where:

r is the radius of the circumference

mAB is the angle of the arc

arc length = $\frac{mAB.2.\pi.r }{360}$

arc length = $\frac{90.2.3.14.6}{360}$

arc length = 9.4

The arc lenght for the image is 9.4 inches.

b) An <u>arc</u> <u>length</u> is a fraction of the circumference of a circle. To determine the arc length, the ratio of the length of an arc to the circumference is equal to the ratio of the measure of the arc to 360°. So, suppose the arc length is x, for the arc in (b):

$\frac{x}{2.6.\pi } = \frac{130}{360}$