let's recall that d = rt, distance = rate * time.
he went upstream to a distance "d", got tired and came back to his starting point, so he rowed back a distance "d" exactly.
we know the rates, we also know the trip took 2 hours, let's say on the way over he took "t" hours to get there, on the way back he lasted then "2 - t" hours.

![\stackrel{\textit{substituting on the 2nd equation}}{2t=8(2-t)\implies 2t=16-8t}\implies 10t=16\implies t=\cfrac{16}{10}\implies t=\cfrac{8}{5} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{we know that}}{d=2t}\implies d=2\left( \cfrac{8}{5} \right)\implies \stackrel{\textit{3 miles and 1056 feet}}{d=\cfrac{16}{5}\implies d=3\frac{1}{5}}](https://tex.z-dn.net/?f=%5Cstackrel%7B%5Ctextit%7Bsubstituting%20on%20the%202nd%20equation%7D%7D%7B2t%3D8%282-t%29%5Cimplies%202t%3D16-8t%7D%5Cimplies%2010t%3D16%5Cimplies%20t%3D%5Ccfrac%7B16%7D%7B10%7D%5Cimplies%20t%3D%5Ccfrac%7B8%7D%7B5%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Bwe%20know%20that%7D%7D%7Bd%3D2t%7D%5Cimplies%20d%3D2%5Cleft%28%20%5Ccfrac%7B8%7D%7B5%7D%20%5Cright%29%5Cimplies%20%5Cstackrel%7B%5Ctextit%7B3%20miles%20and%201056%20feet%7D%7D%7Bd%3D%5Ccfrac%7B16%7D%7B5%7D%5Cimplies%20d%3D3%5Cfrac%7B1%7D%7B5%7D%7D)
(0,0),(1,3)
slope = (3 - 0) / (1 - 0) = 3/1 = 3
y = mx + b
slope(m) = 3
y int (b).....this is when x = 0...u have point (0,0)...this means ur y int is 0
now sub
y = 3x + 0 which can be written as y = 3x <===
Answer:
A negative number is something like if you have $4 and you give me $5 you would be negative because you owe me $1
Step-by-step explanation:
3x-22+x=180
4x-22=180
4x=202
X=202/4
X=50.5
3(50.5)-22=129.5
5-.5+129.5=180
Answer:
Slope=− 1.083/1.083 =−0.542
x−intercept= 144/13 =11.07692
y−intercept= 144/24 =6.
Step-by-step explanation: