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tekilochka [14]
3 years ago
15

Prove that cos^3x+3cos2x= 4 (cos^6 x-sin^6x)

Mathematics
1 answer:
gavmur [86]3 years ago
5 0
But this isn't true... If x=\dfrac\pi2, you have

\cos^3\dfrac\pi2+3\cos\pi=0-3=-3
4\left(\cos^6\dfrac\pi2-\sin^6\dfrac\pi2\right)=4(0-1)=-4

but of course -3\neq-4.
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Hello! Using what we know, the price of the candy bar at the moment is $1.53, triple the price from 10 years ago. So, triple cents would technically be $0.03. We divide $1.53 and $0.03 and get 51! But, it would not make sense for the price ten years ago to be 51 then go to 1.53, so we make 51 a decimal, 0.51. We can check to see if this correct, by doing 0.51 times 3, because the price is tripling, and we get $1.53! Have an awesome day! :)

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