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wolverine [178]
2 years ago
5

Tom has 2 more than 5 times the number of CD’s that Jane has. Jane has 5 CD’s. Write an

Mathematics
2 answers:
aleksandr82 [10.1K]2 years ago
5 0

Tom has 2 more than 5 times what Jane has, so you would multiply the amount Jane has by 5, then add 2 to that:

Tom  = 5(5) +2

Tom = 25 +2

Tom = 27 CD's.

Soloha48 [4]2 years ago
3 0

Step-by-step explanation:

t=2+5×j

j=5

t=2+5×5

t=27

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-6x + 2y = 10 is written in Standard form.<br> Rewrite it in y=form.
dedylja [7]

Answer:

y = 3x + 5

Step-by-step explanation:

add 6x to each side to get:

2y = 6x + 10

finally, divide each side by 2 to get:

y = 3x + 5

8 0
2 years ago
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A tree house costs $530. You plan to save $10 each week. Your parents will help pay $80 of the cost. Your savings plan can be mo
ivanzaharov [21]
The answer would be 45 weeks, since you do 530-80 since that is the part the parents will foot, which will be 450 left. Then you do that divided by 10 since you plan to save 10 dollars a week and therefore are left with 45 weeks.
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3 years ago
What is 4/17 as a decimal
Stells [14]
<span><span>Step 1: Find a number you can multiply by the bottom of the fraction to make it 10, or 100, or 1000, or any 1 followed by 0s.

</span><span>Step 2: Multiply both top and bottom by that number.

</span><span>Step 3.Then write down just the top number, putting the decimal point in the correct spot (one space from the right hand side for every zero in the bottom number)</span></span><span> 

Hope i helped :[)</span>
6 0
3 years ago
What is 2.33 written as a mixed number in simplest form?
aleksandr82 [10.1K]
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8 0
3 years ago
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The fish population in a certain lake rises and falls according to the formula F = 3000(23 + 11t − t2). Here F is the number of
Gemiola [76]

Answer:

a) On January 1, 2017 the fish population will be the same as the initial population.

b) On September 18th, 2018 the fish population will be zero.

Step-by-step explanation:

Hi there!

a) First, let´s write the function:

F(t) = 3000(23 + 11t − t²)

The population on January 1, 2006 is the population at t = 0. Then:

F(0) = 3000(23 + 11· 0 - 0²)

F(0) = 3000 · 23 = 69000

This will be the population every time at which t² - 11t = 0. Then let´s find the other value of t (besides t = 0) that makes that expression to be zero:

t² - 11t = 0

t(t - 11) = 0

t = 0

and

t - 11 = 0

t = 11

On January 1, 2017 (2006 + 11), the fish population will be the same as the initial population.

b) We have to obtain the value of t at which F(t) = 0

F(t) = 3000(23 + 11t − t²)

0 = 3000(23 + 11t − t²)

divide both sides of the equation by 3000

0 = 23 + 11t − t²

Let´s solve this quadratic equation using the quadratic formula:

a = -1

b = 11

c = 23

x = [-b ± √(b² - 4ac)] / 2a

x = 12.8  ( the other value of x is negative and therefore discarded).

After 12.8 years all the fish in the lake will have died.

If 1 year is 12 months, 0.8 years will be:

0.8 years · 12 months/year = 9.6 months

If 1 month is 30 days, 0.6 month will be:

0.6 month · 30 days / month = 18 days

All the fish will have died after 12 years, 9 months and 18 days from January 1, 2006. That is, on September 18th, 2018.

7 0
3 years ago
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