You want the equation for a line that goes through the data points (0, 248) and (5, 277). The slope is ∆y/∆x = (277-248)/(5-0) = 29/5 = 5.8. The first data point is the y-intercept, so your equation in slope-intercept form is
... y = 5.8x + 248 . . . . . . where y is MWh of generation and x is years since 2007.
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∆y is read "delta y". It means "the change in y".
Answer:
Probability that a Niffler can hold more than 32 pounds of shiny objects in their pouch is 0.1515.
Step-by-step explanation:
We are given that the amount a Niffler can hold in their pouch is approximately normally distributed with a mean of 25 pounds of shiny objects and a standard deviation of 6.8 pounds.
Let X = <u><em>amount a Niffler can hold in their pouch</em></u>
So, X ~ Normal()
The z score probability distribution for normal distribution is given by;
Z = ~ N(0,1)
where, = population mean = 25 pounds
= standard deviation = 6.8 pounds
Now, the probability that a Niffler can hold more than 32 pounds of shiny objects in their pouch is given by = P(X > 32 pounds)
P(X > 32 pounds) = P( >
) = P(Z > 1.03) = 1 - P(Z
1.03)
= 1 - 0.8485 = 0.1515
<em>The above probability is calculated by looking at the value of x = 1.03 in the z table which has an area of 0.8485.</em>
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Hence, the probability that a Niffler can hold more than 32 pounds of shiny objects in their pouch is 0.1515.