Answer and Explanation:
Given : The random variable x has the following probability distribution.
To find :
a. Is this probability distribution valid? Explain and list the requirements for a valid probability distribution.
b. Calculate the expected value of x.
c. Calculate the variance of x.
d. Calculate the standard deviation of x.
Solution :
First we create the table as per requirements,
x P(x) xP(x) x² x²P(x)
0 0.25 0 0 0
1 0.20 0.20 1 0.20
2 0.15 0.3 4 0.6
3 0.30 0.9 9 2.7
4 0.10 0.4 16 1.6
∑P(x)=1 ∑xP(x)=1.8 ∑x²P(x)=5.1
a) To determine that table shows a probability distribution we add up all five probabilities if the sum is 1 then it is a valid distribution.


Yes it is a probability distribution.
b) The expected value of x is defined as

c) The variance of x is defined as

d) The standard deviation of x is defined as



$3,600 is 0.8% (or 80%) of $4,500.
Step-by-step explanation:
f(5) = 2(5) = 10
hope this helps
Answer:
AE = 70
Step-by-step explanation:
Given that ACE is a triangle and B , D , F are mid-points of AC, CE, AE respectively.
⇒ BF, FD, BD are mid-segments.
Mid-segment is a line segment joining mid points of two sides of a triangle,
And it as two properties :
1) mid-segment is always parallel to the third side
2) mid-segment is half in length of the third side
⇒ Here, BD is the mid-segment and is parallel to third side AE
And also BD is half of AE
⇒ AE = 2×BD = 2×35
⇒ AE = 70.