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9 months ago

Please help!!!!!! UrGenT

Mathematics

1 answer:

Arlecino [84]9 months ago

4 0

We can’t see that it’s black

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Can any help me please

PSYCHO15rus [73]

A = 8i + 6j
b = 4i + 5j

ab = (8i + 6j)(4i + 5j)
ab = 8i(4i + 5j) + 6j(4i + 5j)
ab = 8i(4i) + 8i(5j) + 6j(4i) + 6j(5j)
ab = 32i² + 40ij + 24ij + 30j²
ab = 32i² + 64ij + 30j²
ab = <32, 30>

The answer is D.

4 0

2 years ago

If f(x)=2x and g(x)=1/x what is the domain of (f•g)(x)

Leona [35]

Answer:g(x) is the domain...

Step-by-step explanation:

I don't say u must have to mark my ans as brainliest but if it has really helped u plz don't forget to thnk me...

3 0

2 years ago

Read 2 more answers

Please help!!! I need anybody help who knows the answer.

Tpy6a [65]

Your answer should be C sorry if i'm wrong, hope it helps tho

4 0

2 years ago

You currently make $18.32 an hour, get time and a half for anything over 40 hours, and a 10% commission on

german

Answer: b

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

A bag of marbles contains 12 red marbles 8 blue marbles and 5 green marbles. If three marbles are pulled out find each of the pr

worty [1.4K]

Answer: The probability of pulling a red marble is 48%, probability of pulling a blue marble is 32%, probability of pulling a green marble is 20%

and

the probability of pulling three green marbles out with replacement is 0.8%.

Step-by-step explanation: Given that a bag of marbles contains 12 red marbles 8 blue marbles and 5 green marbles.

Let S be the sample space for the experiment of pulling a marble.

Then, n(S) = 12 + 8 + 5 = 25.

Let, E, F and G represents the events of pulling a red marble, a blue marble and a green marble respectively.

The, n(E) = 12, n(F) = 8 and n(G) = 5.

Therefore, the probabilities of each of these three events E, F and G will be

$P(E)=\dfrac{n(E)}{n(S)}=\dfrac{12}{25}=\dfrac{12}{25}\times100\%=48\%,\\\\\\P(F)=\dfrac{n(F)}{n(S)}=\dfrac{8}{25}=\dfrac{8}{25}\times100\%=32\%,\\\\\\P(G)=\dfrac{n(G)}{n(S)}=\dfrac{5}{25}=\dfrac{5}{25}\times100\%=20\%.$

Now, the probability of pulling three green marbles out with replacement is given by

$P(G)\times P(G)\times P(G)=\dfrac{5}{25}\times\dfrac{5}{25}\times \dfrac{5}{25}=\dfrac{1}{125}=\dfrac{1}{125}\times100\%=0.8\%.$

Thus, the probability of pulling a red marble is 48%, probability of pulling a blue marble is 32%, probability of pulling a green marble is 20%

and

the probability of pulling three green marbles out with replacement is 0.8%.

4 0

3 years ago