For a regular tessellation, the shapes can be duplicated infinitely to fill a plane such that there is no gap. The only shapes that can form regular tessellations are equilateral traingle(all sides are equal. This means that it can be turned to any side and it would remain the same), square and regular hexagon. Looking at the given options, we have
Shape Tessellate?
Octagon No
Hexagon Yes
Pentagon No
Square Yes
Triangle No(unless it is specified that it is an equilateral triangle)
Three of the four towns are on the vertices of the triangle ΔCBD, through
which the bearing can calculated.
<h3>Response:</h3>
- The bearing of D from B is approximately <u>209.05°</u>
<h3>Method by which the bearing is found;</h3>
From the given information, we have;
AC = AB = 25 km
∠BAC = 90° (definition of angle between north and east)
ΔABC = An isosceles right triangle (definition)
∠ACD = ∠ABC = 45° (base angles of an isosceles right triangle)
The bearing of <em>D</em> from <em>B</em> is the angle measured from the north of <em>B</em> to the
direction of <em>D.</em>
<em />
Therefore;
- The bearing of D from B ≈ 90° + (180° - 60.945°) = <u>209.05°</u>
Learn more about bearings in mathematics here:
brainly.com/question/10710413
(fg)(x)= x³ - 7x² - 9x + 8
domain is (-∞,∞)
Given: f(x)= x-8, g(x)= x² +1x - 1
To find (fg)(x) we multiply f(x) and g(x)
(fg)(x) = f(x) * g(x)
(fg)(x)= (x-8) (x²+x-1)
(fg)(x)= x³ + x² - x - 8x² - 8x +8
(fg)(x)= x³ - 7x² - 9x + 8
we know, domain for all cubic function is set of all real numbers
domain is (-∞,∞)
Know more about "functions" here: brainly.com/question/12431044
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x + 16 = 64 |subtract 16 from both sides
x = 48
1 2 4 8 and 16 are the factors
