Answer:
(x + 14)² + (y – 21/2)² = 1
Step-by-step explanation:
The equation of a circle can be written as seen below
(x – h)² + (y – k)² = r²
Where (h,k) is at the center and r = radius
We are given that the radius is 1
We are also given that the center is at (-14,21/2)
So we know that r = 1, h = -14, and k = 21/2
So to find the equation of the circle we simply substitute these values into the equation of a circle
Equation of a circle: (x – h)² + (y – k)² = r²
r = 1, h = -14, and k = 21/2
Substitute values
(x – (-14))² + (y – 21/2)² = 1²
1^2 = 1
The two negative signs before the 14 cancel out and it changes to + 14
The equation of a circle with a center at (-14,21/2) and a radius of 1 is (x + 14)² + (y – 21/2)² = 1
Answer:
<h2>
A. ¹²/₅</h2>
Step-by-step explanation:
There is no solution for system of equations: 
if: 
so first, we we need to transform the equations to the form where the coefficients at y will be the same:
Now we have b₁=b₂ and c₁≠c₂ so the system has no solution if a₁=a₂
5k = 12
÷5 ÷5
k = ¹²/₅
I say its 11. Since the distance between the two points is 11.
Answer:
No
Step-by-step explanation:
I am right. Trust me.
Answer:
3
Step-by-step explanation:
24 + (-1) = 23, 12 + (-2) = 10, 8 + (-3) = and 6 + (- 4) = 2, none of the sums are equal to 3, therefore b = 3 would give a prime quadratic. The correct answer is then A. 3
