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dexar [7]
3 years ago
10

Explain why it does not matter what letter or symbol is used to find and unknown number?

Mathematics
1 answer:
boyakko [2]3 years ago
8 0
It dose not matter what letter or symbol to find the unknown number because you are only using something to represent that number.
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In the figure below, ∠ABC ≅ ∠DEC and ∠GFE ≅ ∠DCE. Point C is the point of intersection between segment AG and segment BD, while
I am Lyosha [343]

Answer:

See Below.

Step-by-step explanation:

We are given that:

\angle ABC \cong \angle DEC\text{ and } \angle GFE \cong \angle DCE

By vertical angles:

\displaystyle \angle DEC\cong \angle GEF\text{ and } \angle DCE\cong \angle ACB

Hence, by substitution:

\displaystyle \angle ABC\cong \angle GEF\text{ and } \angle GFE\cong \angle ACB

Then by Angle-Angle Similarity:

\Delta ABC \sim \Delta GEF

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3 years ago
Find the HIGHEST Common<br> and lowest common multple<br> of 36 and 48 using<br> prime factors
Vesnalui [34]

Answer:

Step-by-step explanation:

Least common multiple can be found by multiplying the highest exponent prime factors of 36 and 48. First we will calculate the prime factors of 36 and 48.

Prime Factorization of 36

Prime factors of 36 are 2, 3. Prime factorization of 36 in exponential form is:

36 = 22 × 32

Prime Factorization of 48

Prime factors of 48 are 2, 3. Prime factorization of 48 in exponential form is:

48 = 24 × 31

Now multiplying the highest exponent prime factors to calculate the LCM of 36 and 48.

LCM(36,48) = 24 × 32

LCM(36,48) = 144

List of positive integer factors of 36 that divides 36 without a remainder.

1, 2, 3, 4, 6, 9, 12, 18

Factors of 48

List of positive integer factors of 48 that divides 36 without a remainder.

1, 2, 3, 4, 6, 8, 12, 16, 24

Greatest Common Factor Number

We found the factors and prime factorization of 36 and 48. The biggest common factor number is the GCF number.

So the greatest common factor 36 and 48 is 12.

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3 years ago
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Answer:

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Step-by-step explanation:

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4 years ago
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soldi70 [24.7K]

Answer:  c

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\left[\begin{array}{cc}5&2\\3&-1\end{array}\right] \times \left[\begin{array}{c}2\\3\end{array}\right] =\left[\begin{array}{c}5(2)+2(3)\\3(2)-1(3)\\\end{array}\right] = \left[\begin{array}{c}16\\3\end{array}\right]

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3 years ago
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choli [55]

Answer:

i am pretty sure the answer is

Step-by-step explanation:

15°

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