Find the coordinates of the x- and y-intercepts for an ellipse with the equation (x+1)^2/9 + (y-2)^2/8 = 1
1 answer:
Answer:
- x-intercepts: -1±√4.5
- y-intercepts: 2±8/3
Step-by-step explanation:
The x-intercepts are where y = 0.
(x +1)^2/9 +(0 -2)^2/8 = 1
(x +1)^2/9 +1/2 = 1 . . . . . simplify a bit
(x +1)^2 = 9/2 . . . . . . . . .subtract 1/2, multiply by 9; next: square root, add -1
x = -1 ±√4.5 . . . . . x-intercepts
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The y-intercepts are where x=0.
(0+1)^2/9 +(y-2)^2/8 = 1
1/9 + (y -2)^2/8 = 1 . . . . . simplify a bit
(y -2)^2 = 64/9 . . . . . . . . subtract 1/9, multiply by 8,
y = 2 ±8/3 . . . . . . take the square root, add 2 . . . . y-intercepts
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Answer:
Step-by-step explanation:
We have to find the derivative of the following function:
Now, differentiating both sides with respect to x we get,
⇒ (Answer)
{Since, we know that, and
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Remark
You must use the sin law to find this.
Multiply through by 12
12 * *12
0.5269 = sin(x)
Now you have to use the inverse of the sine function.
Use your calculator for that
2nd F
sin-1
(0.5269)
= 31.79 degrees. <<<<<< Answer.
There sometimes is a second answer. I don't think there is in this case.