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3 years ago

Find a common multiple between 30 and 42 that is bigger than them.

Mathematics

2 answers:

Wittaler [7]3 years ago

6 0

Answer:

210

Step-by-step explanation:

GCF(30,42) = 6

LCM(30,42) = ( 30 × 42) / 6

LCM(30,42) = 1260 / 6

LCM(30,42) = 210

Elan Coil [88]3 years ago

5 0

1260

1260 is a multiple of 30 and 42.
30(42)=1260,
multiplying both of these numbers means that the result will always be a common multiple.

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Is 4m equal to 400dm

erica [24]

It is not.

400 decimeters = 4,000 cm

4,000 cm = 40 m

6 0

3 years ago

Please help me I'm stuck on this one

Colt1911 [192]

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3 years ago

Solve by Elimination:<br> 8x + 6y = -5<br> 10x + 6y= -13

jonny [76]

Answer:

x= -4 and y= 27/6

Step-by-step explanation:

-(8x + 6y = -5) which converts to -8x -6y = 5

10x + 6y = -13

simplify from there

-8x + 10x = 2x ; -6y + 6y = 0 ; 5 - 13 = -8

soo, now you have

2x = -8

x = -4

then, plug in to find y

8(-4) + 6y = -5

-32 + 6y = -5 add 32 on both sides

6y = 27 divide both sides by 6

y= 27/6 or 4.5

8 0

3 years ago

Given O below, If AB and BC are congruent, what is the measure of chord BC?

zhuklara [117]

Since, AB and BC are the same length, the measure of the chord for BC would be 12.5 units

3 0

3 years ago

Read 2 more answers

A projectile is launched into the air. The function h(t) = –16t2 + 32t + 128 gives the height, h, in feet, of the projectile t s

Zinaida [17]

Answer:

t = 4 seconds

Step-by-step explanation:

The height of the projectile after it is launched is given by the function :

$h(t)=-16t^2+32t+128$

t is time in seconds

We need to find after how many seconds will the projectile land back on the ground. When it land, h(t)=0

So,

$-16t^2+32t+128=0$

The above is a quadratic equation. It can be solved by the formula as follows :

$t=\dfrac{-b\pm \sqrt{b^2-4ac} }{2a}$

Here, a = -16, b = 32 and c = 128

$t=\dfrac{-32\pm \sqrt{(32)^2-4\times (-16)(128)} }{2\times (-16)}\\\\t=\dfrac{-32+ \sqrt{(32)^2-4\times (-16)(128)} }{2\times (-16)}, \dfrac{-32\- \sqrt{(32)^2-4\times (-16)(128)} }{2\times (-16)}\\\\t=-2\ s\ \text{and}\ 4\ s$

Neglecting negative value, the projectile will land after 4 seconds.

4 0

3 years ago