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3 years ago

Find a common multiple between 30 and 42 that is bigger than them.

Mathematics

2 answers:

Wittaler [7]3 years ago

6 0

Answer:

210

Step-by-step explanation:

GCF(30,42) = 6

LCM(30,42) = ( 30 × 42) / 6

LCM(30,42) = 1260 / 6

LCM(30,42) = 210

Elan Coil [88]3 years ago

5 0

1260

1260 is a multiple of 30 and 42.
30(42)=1260,
multiplying both of these numbers means that the result will always be a common multiple.

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Answer:

Step-by-step explanation:

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2 years ago

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Step-by-step explanation:

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3 years ago

Read 2 more answers

If 90 percent of automobiles in Orange County have both headlights working, what is the probability that in a sample of eight au

Alex17521 [72]

Answer:

$P(X \geq 7) = P(X=7) +P(X=8)$

And we can find the individual probabilities using the probability mass function

$P(X=7)=(8C7)(0.9)^7 (1-0.9)^{8-7}=0.3826$

$P(X=8)=(8C8)(0.9)^8 (1-0.9)^{8-8}=0.4305$

And replacing we got:

$P(X \geq 7) = P(X=7) +P(X=8)=0.3826 +0.4305=0.8131$

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Let X the random variable of interest "number of automobiles with both headligths working", on this case we now that:

$X \sim Binom(n=8, p=0.9)$