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Alika [10]
4 years ago
13

The rates of return on the investments in a large portfolio had mound shapeddistribution, with a mean of 20% and a standard devi

ation of 10%.
a. What proportion of the investments had a return of between 10% and 30%?b. What proportion of investments had a return that was either less than 10% or morethan 30%?
Mathematics
1 answer:
Scilla [17]4 years ago
6 0

Answer:

a) 68% of the investments had a return of between 10% and 30%.

b) 32% of investments had a return that was either less than 10% or morethan 30%.

Step-by-step explanation:

We can use the Empirical Rule to solve this question:

The Empirical Rule states that, for a normally distributed random variable:

68% of the measures are within 1 standard deviation of the mean. This also means that 32% of the measures are more than 1 standard deviation from the mean.

95% of the measures are within 2 standard deviation of the mean. This also means that 5% of the measures are more than 2 standard deviations from the mean.

99.7% of the measures are within 3 standard deviations of the mean. This also means that 0.3% of the measures are more than 3 standard deviations from the mean.

In this problem, we have that:

Mean = 20%.

Standard deviation = 10%.

a. What proportion of the investments had a return of between 10% and 30%?

10 is the mean subtracted by 1 one standard deviation

30 is one standard deviation added to the mean.

So 10 and 30 are within 1 standard deviation of the mean. So 68% of the investments had a return of between 10% and 30%.

b. What proportion of investments had a return that was either less than 10% or morethan 30%?

This is the proportion of investments that were farther than one standard deviation of the mean.

By the Empirical Rule, 32% of investments had a return that was either less than 10% or morethan 30%.

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Step-by-step explanation:

10 dm = 100 cm = 1 m.

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Correct ☑ ✔ Question :-

Transform in metre

a) 7 dam

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d) 0.5 km

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<h3>Solution ✔</h3>

a) 7 dam

1 dam = 10 m

so, 7 dam = 7 × 10 m = 70 m

b) 350 dm

10 dm = 1 m

so, 350 dm = 350/10 = 35 m

c) 57000 mm

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d) 0.5 km

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0.5 km = 1000 × 0.5 = 500 m

e) 750 cm

100 cm = 1 m

750 cm = 750/ 100 = 7.5 m

f) 5.7 dam

1 dam = 10 .

5.7 dam = 5.7 × 10 = 57 m

7 0
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