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GrogVix [38]
3 years ago
14

Simply 3 26/27 + 2 3/4 + 15 1/9

Mathematics
2 answers:
cupoosta [38]3 years ago
7 0
1) 3+2+15=20
2) 3/4= 27/36  1/9=4/36
3) 27/36+4/36=31/36
4) 26/27=936/972   31/36= 637/972
5) 936/972 + 637/972= 1573/972=  1 601/972
victus00 [196]3 years ago
5 0
1,4689,780 I think, hope this helps not sure tho
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A bake
dimulka [17.4K]

Answer:

15 and a half days

Step-by-step explanation:

Since they earn $12's each day you would do $186 divided by $12 which would be 15.5 so it would take them 15 and a half days to raise $186.

8 0
3 years ago
Simplify −2xy + 3x − 2xy + 3x <br><br> A. 4xy +6x B. 2xy C. −4xy + 6x D. 4xy − 6x
marysya [2.9K]
First you must combine like terms, the two terms I this expression are x, and xy. So by adding -2xy to -2xy you get -4xy. Next you must add 3x to 3x. This gives you the simplified expression -4xy+6x. Hope this helps
4 0
3 years ago
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Factor the following question x^{2} -9x-36
Klio2033 [76]

Step-by-step explanation:

{x}^{2}  - 9x - 36 \\ (x - 12)(x + 3)

3 0
3 years ago
Find the absolute extrema for f(x,y)=4-x^2-y^4+1/2y^2 over the closed disk D:x^2+y^2 is less than or equal to 1
algol [13]

Find the critical points of f(x,y):

\dfrac{\partial f}{\partial x}=-2x=0\implies x=0

\dfrac{\partial f}{\partial y}=y-4y^3=y(1-4y^2)=0\implies y=0\text{ or }y=\pm\dfrac12

All three points lie within D, and f takes on values of

\begin{cases}f(0,0)=4\\f\left(0,-\frac12\right)=\frac{65}{16}\\f\left(0,\frac12\right)=\frac{65}{16}\end{cases}

Now check for extrema on the boundary of D. Convert to polar coordinates:

f(x,y)=f(\cos t,\sin t)=g(t)=4-\cos^2-\sin^4t+\dfrac12\sin^2t=3+\dfrac32\sin^2t-\sin^4t

Find the critical points of g(t):

\dfrac{\mathrm dg}{\mathrm dt}=3\sin t\cos t-4\sin^3t\cos t=\sin t\cos t(3-4\sin^2t)=0

\implies\sin t=0\text{ or }\cos t=0\text{ or }\sin t=\pm\dfrac{\sqrt3}2

\implies t=n\pi\text{ or }t=\dfrac{(2n+1)\pi}2\text{ or }\pm\dfrac\pi3+2n\pi

where n is any integer. There are some redundant critical points, so we'll just consider 0\le t< 2\pi, which gives

t=0\text{ or }t=\dfrac\pi3\text{ or }t=\dfrac\pi2\text{ or }t=\pi\text{ or }t=\dfrac{3\pi}2\text{ or }t=\dfrac{5\pi}3

which gives values of

\begin{cases}g(0)=3\\g\left(\frac\pi3\right)=\frac{57}{16}\\g\left(\frac\pi2\right)=\frac72\\g(\pi)=3\\g\left(\frac{3\pi}2\right)=\frac72\\g\left(\frac{5\pi}3\right)=\frac{57}{16}\end{cases}

So altogether, f(x,y) has an absolute maximum of 65/16 at the points (0, -1/2) and (0, 1/2), and an absolute minimum of 3 at (-1, 0).

5 0
3 years ago
HAVE A NICE DAY <br> WILL GIVE BRAINLST :)
muminat

Answer:

1)  2 and 6 ; 4 and 8 ; 1 and 5 ; 3 and 7

2)  3 and 6 ; 4 and 5

3) 1 and 8 ; 2 and 7

7 0
3 years ago
Read 2 more answers
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