<span>I am sure its Kiribati</span>
Answer:
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P(R I Q) = P(RnQ) / P(Q) = 0.1 Therefore P(RnQ) = 0.1 X 0.35 = 0.035 (The intersection in the centre of a Venn Diagram)
P(RnQ') = 0.15 In a Venn Diagram this is R but excluding the centre intersection with Q. Therefore P(R) = P(RnQ') + P(RnQ) = 0.15 + 0.035 = 0.185
P(RUQ) = 0.15 + 0.035 + 0.315 = 0.5 so 0.5 must be outside the Venn Diagram circles.
Explanation:
hope this helps
Part 1/
5 + x - 14 = x - 7
We’ll cancel (X) from both sides;
5 - 14 = -7
-9 = -7
Since, -9 = -7 is False, there is no solution.
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Part2/
If we use x = -2, 0, 3
1) Case of X = -2
5 + (-2) - 14 = (-2) - 7
5 - 2 - 14 = -2 - 7
3 - 14 = -9
-11 = -9 .... False / No Solution
2) Case of X = 0
5 + (0) - 14 = (0) - 7
5 - 14 = -7
-9 = -7 ... False / No Solution
3) Case of X = 3
5 + (3) - 14 = (3) - 7
8 - 14 = -4
-6 = -4 ... False / No Solution
