To factor a quadratic of the form ax^2+bx+c you need to find two values, j and k, which satisfy two conditions...
jk=ac=12 and j+k=b=8, so j and k must be 2 and 6
Then the factors are just (a+j)(a+k), in this case:
(a+2)(a+6)
So the missing term was 6
Answer:
graph c is the correct answer
Multiply 9 books by 55% by doing
9 x .55 = 4.95
We can't have 4.95 books, though so it rounds down to 4 because you can't just add another .05.
Answer:
![\frac{x^{2} }{4312 } + \frac{y^{2} }{8281 }](https://tex.z-dn.net/?f=%5Cfrac%7Bx%5E%7B2%7D%20%7D%7B4312%20%7D%20%2B%20%5Cfrac%7By%5E%7B2%7D%20%7D%7B8281%20%7D)
Step-by-step explanation:
Since the foci are at(0,±c) = (0,±63) and vertices (0,±a) = (0,±91), the major axis is the y- axis. So, we have the equation in the form (with center at the origin)
.
We find the co-vertices b from b = ±√(a² - c²) where a = 91 and c = 63
b = ±√(a² - c²)
= ±√(91² - 63²)
= ±√(8281 - 3969)
= ±√4312
= ±14√22
So the equation is
![\frac{x^{2} }{(14\sqrt{22}) ^{2} } + \frac{y^{2} }{91^{2} } = \frac{x^{2} }{4312 } + \frac{y^{2} }{8281 }](https://tex.z-dn.net/?f=%5Cfrac%7Bx%5E%7B2%7D%20%7D%7B%2814%5Csqrt%7B22%7D%29%20%5E%7B2%7D%20%7D%20%2B%20%5Cfrac%7By%5E%7B2%7D%20%7D%7B91%5E%7B2%7D%20%7D%20%3D%20%5Cfrac%7Bx%5E%7B2%7D%20%7D%7B4312%20%7D%20%2B%20%5Cfrac%7By%5E%7B2%7D%20%7D%7B8281%20%7D)