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ddd [48]
3 years ago
10

Determine whether w= 1.8 is a solution to the equation 9.5 = w/0.2

Mathematics
2 answers:
mina [271]3 years ago
8 0

Answer:

No

Step-by-step explanation:

1.8/0.2 = 9 not 9.5

blagie [28]3 years ago
6 0

Answer:

No it not W = 1.9

Step-by-step explanation:

Because from

9.5 = w/0.2

W = 9.5 x 0.2

W = 1.9

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There's a piece of a pyramid is a rectangle with a width of 4.6 cm and the length of the 9 cm. What is the height in centimeters
Dominik [7]

Answer:

6cm

Step-by-step explanation:

Given data

Width= 4.6cm

Length= 9cm

Volume= 82.8cm^3

The expression for the volume is given as

V= lwh/3

82.8= 9*4.6*h/3

cross multiply

82.8*3= 9*4.6*h

248.4= 41.4h

h= 248.4/41.4

h= 6cm

8 0
3 years ago
Help please,
Rama09 [41]

Answer:

-4,5

Step-by-step explanation:

4 0
3 years ago
The breaking strengths of cables produced by a certain manufacturer have a mean, u, of 1750 pounds, and a standard deviation of
AlladinOne [14]

Answer:

We accept the null hypothesis that the  breaking strength mean is less and equal to 1750 pounds and has not increased.

Step-by-step explanation:

The null and alternative hypotheses are stated as

H0:  u ≥ 1750   i.e the mean is less and equal to 1750

against the claim

Ha: u > 1750  ( one tailed test)  the mean is greater than 1750

Sample mean = x`= 1754

Population mean = u = 1750

Population deviation= σ = 65 pounds

Sample size= n = 100

Applying the Z test

z= x`- u / σ/ √n

z= 1754- 1750 / 65/ √100

z= 4/6.5

z= 0.6154

The significance level alpha = 0.1

The z - value at 0.1 for one tailed test is ± 1.28

The critical value is z > z∝.

so

0.6154 is < 1.28

We accept the null hypothesis that the  breaking strength mean is less and equal to 1750 pounds and has not increased.

8 0
3 years ago
What is the domain of the function f(x) = sqrt 7x+21
timurjin [86]

\text{if is}\ f(x)=\sqrt{7x+21}\ \text{then the domain is:}\\\\7x+21\geq0\ \ \ |-21\\7x\geq-21\ \ \ \ |:7\\x\geq-3\to x\in[-3;\ \infty)


\text{If is}\ f(x)=\sqrt{7x}+21\ \text{then the domain is:}\\\\7x\geq0\ \ \ |:7\\x\geq0\to x\in[0;\ \infty)

6 0
3 years ago
Given: AB is the perpendicular bisector of IK. Name two lengths that are equal.
Paha777 [63]
Since AB is the perpendicular bisector of IK, it separates IK into 2 equal segments. So, the two halves of IK are the same length. (From AB to K, and from AB to I) <span />
5 0
3 years ago
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