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kiruha [24]
3 years ago
9

Which answer is the same as moving the decimal in 12.9 two places to the right?

Mathematics
1 answer:
blsea [12.9K]3 years ago
8 0
The answer is C.
12.9*100=1290
Since 1290 can be represented as 1290. we know that the decimal was moved to the right twice.
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Use matrices and elementary row to solve the following system:
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I assume the first equation is supposed to be

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and not

5x-3x+2x=4x=13

As an augmented matrix, this system is given by

\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\4&-2&4&12\end{array}\right]

Multiply through row 3 by 1/2:

\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\2&-1&2&6\end{array}\right]

Add -1(row 2) to row 3:

\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\0&0&5&5\end{array}\right]

Multiply through row 3 by 1/5:

\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\0&0&1&1\end{array}\right]

Add -2(row 3) to row 1, and add 3(row 3) to row 2:

\left[\begin{array}{ccc|c}5&-3&0&11\\2&-1&0&4\\0&0&1&1\end{array}\right]

Add -3(row 2) to row 1:

\left[\begin{array}{ccc|c}-1&0&0&-1\\2&-1&0&4\\0&0&1&1\end{array}\right]

Multiply through row 1 by -1:

\left[\begin{array}{ccc|c}1&0&0&1\\2&-1&0&4\\0&0&1&1\end{array}\right]

Add -2(row 1) to row 2:

\left[\begin{array}{ccc|c}1&0&0&1\\0&-1&0&2\\0&0&1&1\end{array}\right]

Multipy through row 2 by -1:

\left[\begin{array}{ccc|c}1&0&0&1\\0&1&0&-2\\0&0&1&1\end{array}\right]

The solution to the system is then

\boxed{x=1,y=-2,z=1}

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I =PRT

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Angle W and angle X are congruent. If their sum is 121 degrees, what is the measure of angle X?
Nimfa-mama [501]
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<em>The correct answer is third from the top.</em>

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<em>Let's count how many times each number occurs in this series of numbers.</em>

<em>row of numbers</em>

<em>15 </em>+

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<em>17 </em>+ + +

<em>18 </em>+ + +

<em>19 </em>+ + +

<em>20 not</em>

<em>21 </em>+ +

<em>22 </em>+

<em>23 </em>+

<em>24 </em>+

<em>25 not</em>

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3 years ago
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