LAST QUESTION ON MY TOPIC!!! PLEASE
1 answer:
You might be interested in
Answer:
Step-by-step explanation:
Given
Joaquin's score is
and Trisha's score is
Arranging score in order of value we get
Joaquin's :
Trisha's :
as no of values is even therefore their median is
Joaquin's
Trisha's
Therefore median of Joaquin's is lower
Thus Joaquin wins the game
Look at the picture.
1)|AM| = |MB| = x
|AN| = |NC| = y
|BC| = 2y - 2x = 2(y - x)
|MN| = y - x
Therefore |BC| = 2|MN|
2)|AM| = |MB| = x
|AN| = |NC| = y
|BC| = 2y - 2x = 2(y - x)
|MN| = y - x
Therefore |BC| = 2|MN|
1)|AM| = |MB| = x
|AN| = |NC| = y
|BC| = 2y - 2x = 2(y - x)
|MN| = y - x
Therefore |BC| = 2|MN|
2)|AM| = |MB| = x
|AN| = |NC| = y
|BC| = 2y - 2x = 2(y - x)
|MN| = y - x
Therefore |BC| = 2|MN|