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3 years ago

How would you find the missing value? 15/4=5/x

Mathematics

1 answer:

viktelen [127]3 years ago

7 0

Using the intersecting chord theorem you multiply the two lengths of one line together to equal the multiplication of the two dimensions on the second line.

The answer would be 15(4) = 5x

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Can someone help i dont really understand it

saw5 [17]

Answer:

I believe your answer is d

Step-by-step explanation:

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2 years ago

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Find the formula an for the nth term of the geometric sequence satisfying the following conditions: a1 = -2,

Alexeev081 [22]

Answer:

Step-by-step explanation:

a1 = - 2

an = a1 * r^(n - 1)

a6 = -486

-486 = - 2 * r^(6-1) Divide by 2

243 = r^5

The largest value that r could be is 3.

4^5 = 1024

(243)^(1/5) = 3

So the general formula

an = -2*(3)^(n - 1)

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2 years ago

Given the function g(x) = |x-5|, describe the graph of the function, including the vertex, domain, and range.

kari74 [83]

Answer:

Step-by-step explanation:

The graph will open upwards

Shifted to the right by 5

Vertex: (5,0)

Domain: x= All Real Numbers

Range: y $\geq$ 0

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1 year ago

Solve the initial value problem: y'(x)=(4y(x)+25)^(1/2) ,y(1)=6. you can't really tell, but the '1/2' is the exponent

goblinko [34]

Answer:

$y(x)=x^2+5x$

Step-by-step explanation:

Given: $y'=\sqrt{4y+25}$

Initial value: y(1)=6

Let $y'=\dfrac{dy}{dx}$

$\dfrac{dy}{dx}=\sqrt{4y+25}$

Variable separable

$\dfrac{dy}{\sqrt{4y+25}}=dx$

Integrate both sides

$\int \dfrac{dy}{\sqrt{4y+25}}=\int dx$

$\sqrt{4y+25}=2x+C$

Initial condition, y(1)=6

$\sqrt{4\cdot 6+25}=2\cdot 1+C$

$C=5$

Put C into equation

Solution:

$\sqrt{4y+25}=2x+5$

$4y+25=(2x+5)^2$

$y(x)=\dfrac{1}{4}(2x+5)^2-\dfrac{25}{4}$

$y(x)=x^2+5x$

Hence, The solution is $y(x)=\dfrac{1}{4}(2x+5)^2-\dfrac{25}{4}$ or $y(x)=x^2+5x$

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3 years ago

Which composition of transformations maps figure RSTUV to figure R"S"T"U"V"?

Sergeu [11.5K]

Answer:

option: B is correct

A reflection across line n followed by a 270° rotation about point P.

Step-by-step explanation:

Clearly from the figure we could see that the graph is first reflected across the given line n such that we obtain the figure R'S'T'V'U' and then it is rotated 270° across the point P so that we obtain the figure R"S"T"U"V".

Hence, option B is correct.

( A reflection across line n followed by a 270° rotation about point P )

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3 years ago

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