I can't quite remember how to approach this one, I have three others, but I think I could solve them if someone helped walked me
through this one to jog my memory.
Solve the quadratic equation by completing the square.
x^2-10x+12=0
First, choose the appropriate form and fill in the blanks with the correct numbers.
Then, solve the equation.
(x+[])^2=[]
(x-[])^2=[]
If there is more than one solution, separate them with commas.
Solution:
x = []
Solve the quadratic equation by completing the square.
x^2-10x+12=0
First, choose the appropriate form and fill in the blanks with the correct numbers.
Then, solve the equation.
(x+[])^2=[]
(x-[])^2=[]
If there is more than one solution, separate them with commas.
Solution:
x = []
1 answer:
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Answer:
Step-by-step explanation:
Given: The radius of circle O is r, and the radius of circle X is r'.
To prove: Circle O is similar to circle X.
Proof: Move the center of the smaller circle onto the center of the largest circle. Translate the circle X by the vector XA onto circle O. The circles now have the same center.
A dilation is needed to increase the size of circle X to coincide with the circle O. A value which when multiplied by r' will create r.
The scale factor x to increase X:
⇒
A translation followed by a dilation with scale factor will map one circle to the other, thus proving the given both circles similar.
Therefore, circle O is similar to circle X.
Step-by-step explanation:
Answer:
Step-by-step explanation:
Answer: 3/5
Step-by-step explanation: Using the place value chart, we can see that the decimal 0.6 is 6 tenths. So we can write 0.6 as the fraction 6/10.
Notice however that 6/10 is not in lowest terms.
So we need to divide the numerator and the denominator by the greatest common factor of 6 and 10 which is 2.
So if we divide the numerator and denominator by 2, we get 3/5.
So 0.6 can be written as the fraction 3/5 which is in lowest terms.
Image provided showing the place value chart.
