Trying to factor by splitting the middle term
Factoring <span> b2-4b+4</span>
The first term is, <span> <span>b2</span> </span> its coefficient is <span> 1 </span>.
The middle term is, <span> -4b </span> its coefficient is <span> -4 </span>.
The last term, "the constant", is <span> +4 </span>
Step-1 : Multiply the coefficient of the first term by the constant <span> 1 • 4 = 4</span>
Step-2 : Find two factors of 4 whose sum equals the coefficient of the middle term, which is <span> -4 </span>.
<span><span> </span></span>
<span><span>-4 + -1 = -5</span><span> -2 + -2 = -4 That's it</span></span>
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -2 and -2
<span>b2 - 2b</span> - 2b - 4
Step-4 : Add up the first 2 terms, pulling out like factors :
b • (b-2)
Add up the last 2 terms, pulling out common factors :
2 • (b-2)
Step-5 : Add up the four terms of step 4 :
(b-2) • (b-2)
Which is the desired factorization
In this question , we have to find the postulate that is illustrated for the real numbers
The postulate is Additive inverse postulate which states that
Where a is the real number and -a is the opposite of a. It states that , if opposite of a number is added with the number, the result is 0 .
<span>14:42 = 14/42 = 1/3
</span>This ones right sorry answered wrong question lol
(-3x)⁴
Basically, just do this :
(-3x) × (-3x) × (-3x) × (-3x)
So now you have 9x² × 9x²
9 × 9 = 81
x² × x² = x⁴
So, your answer is 81x⁴
~Hope I helped!~
Answer:
7
Step-by-step explanation:
Using fundamental theorem of algebra, there should be 7 roots, if you count multiplicity.
If you're only counting distinct roots, then there should be 4 roots.
