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enot [183]
3 years ago
15

in a bag of marbles, you have 3 green, two yellow, six blue, and nine red marbles. What is the probability of picking a red marb

le from the bag?
Mathematics
1 answer:
BlackZzzverrR [31]3 years ago
3 0
So first add all of the marbles together: 3+2+6+9=20
Because there are 20 marbles together, that would be your denominator. 
All of the other numbers would be your numerator. So you would have:

3/20 green marbles
2/20 yellow marbles
6/20 blue marbles
9/20 red marbles

So your answer would be the probability of picking a red marble from the bag is 9/20 or 45%

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5c+16.5=13.5+10c PLease answer quicly
frosja888 [35]
Remember you can do anything to an equation as long as you do it to both sides

5c+16.5=13.5+10c
minus 5c both sides
16.5=13.5+5c
minus 13.5 from both sides
3=5c
divide both sides by 5
3/5=c
4 0
3 years ago
Read 2 more answers
What is the slope of the line shown in the graph?
stira [4]
Y= f(x)= ax+b
when x= -1, y= -1
-1= -a+b   | * ( -1)

when x= -3, y=2
2= -3a+b

-3a+b= 2
a -  b=  1
--------------
2a=3
a=3/2   is the slope


7 0
2 years ago
A pool contains 300 L of water. It
Eva8 [605]

Step-by-step explanation:

(300-60)/6,4=37,5

5 0
3 years ago
1.find the sum. (3^3+5x^2+3x-7)+(8x-6x^2+6)<br> 2. Find the Difference: (8x-4x^2+3\)-(x^3+7x^2+3x-8)
vlada-n [284]

1.

(3^3+5x^2+3x-7)+(8x-6x^2+6)=\\\\=27\ \underline{+\,5x^2}\ \underline{ \underline{+\,3x}}-7\ \underline{\underline{\,+8x}}\ \underline{-\,6x^2}+6=\\\\=-x^2+11x+26

or if you mean (3x^3+5x^2+3x-7)+(8x-6x^2+6):

(3x^3+5x^2+3x-7)+(8x-6x^2+6)=\\\\=3x^3\ \underline{+\,5x^2}\ \underline{ \underline{+\,3x}}-7\ \underline{\underline{\,+8x}}\ \underline{-\,6x^2}+6=\\\\=3x^3-x^2+11x-1

2.

(8x-4x^2+3)-(x^3+7x^2+3x-8)=\\\\=\underline{8x}\ \underline{\underline{-\ 4x^2}}+3-x^3\ \underline{\underline{-\,7x^2}}\ \underline{-\,3x}+8=\\\\=-x^3-11x^2+5x+10

3 0
2 years ago
When sending a rectangular package through the U.S. Postal Service, the combined length and girth (perimeter of the cross sectio
weqwewe [10]
Let W = width of package
Let H = height of package
Let L = length of package

The perimeter cab be one of the following:
P = 2(L + W),  or
P = 2(L + H)

The perimeter of the cross section cannot exceed 108 in.
When the width is 10 in, then
 2(L + 10) <= 108
 L + 10 <= 54
 L <= 44 in

When the height is 15 in, then
2(L + 15) <= 108
L + 15 <= 54
L <= 39 in

To satisfy both of these conditions requires that L <= 39 in.

Answer: 39 inches
5 0
2 years ago
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