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Sholpan [36]
3 years ago
13

The life span of a battery is the amount of time the battery will last. The distribution of life span for a certain type of batt

ery is approximately normal with mean 2.5 hours and standard deviation 0.25 hour. Suppose one battery will be selected at random. Which of the following is closest to the probability that the selected battery will have a life span of at most 2.1 hours?
Mathematics
1 answer:
slavikrds [6]3 years ago
7 0

Answer:

0.0548

Step-by-step explanation:

The distribution of life span for a certain type of battery is approximately normal with mean 2.5 hours and standard deviation 0.25 hour.

To find the the probability that a selected battery will have a life span of at most 2.1 hours, we need to first determine the z-score for x=2.1 hours using

z =  \frac{x -  \mu}{ \sigma}

We substitute the values to get:

z =  \frac{2.1 - 2.5}{0.25}  =  - 1.6

We read read -1.6 from the standard normal distribution table to get:

P(X≤2.1)=0.0548

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Scorpion4ik [409]

Answer:

the answer is just 2

Step-by-step explanation:

start at the -3 and move right 3 and up 6 this is a inclined line so the answer will be positive the fraction put the numbers into a rise over run fraction which will be 6/3 which will reduce to 2/1 which is 2.

6 0
2 years ago
What is the reciprocal of 9/14
KATRIN_1 [288]
14/9 because u just flip it to cancel it out
7 0
3 years ago
Read 2 more answers
Help i cant figure this out:(
stealth61 [152]

Answer:

6-2=4

31/5 x 8 = 248/40

15/8 x 5 = 75/40

248-75=173

4 13/40

answers in order

6-2=4

6 1/5 - 1 7/8 = 4 13/40

Hope this helps

Step-by-step explanation:

8 0
2 years ago
the ratio of sadia's age to her father's age is 3:6. The sum of their age is 96 .What is sadia's age​
max2010maxim [7]

We have,

a:b=3:6,a+b=96

Introduce variable x such that a=3x,b=6x

The sum a+b=96 is therefore 9x=96\implies x=10.\overline{6}

So,

a=3\cdot10.\overline{6}=\boxed{32} (sadia's age)

b=6\cdot10.\overline{6}=\boxed{64} (father's age)

Hope this helps :)

4 0
3 years ago
Keith played the first 22 minutes of soccer game lohan then replaced him for the rest of half logan started the second half and
insens350 [35]

Answer:

Logan played for 22 minutes during the second half.

Step-by-step explanation:

Since Keith played the first 22 minutes of a soccer game and Logan then replaced him for the rest of the half, and Logan started the second half and was replaced by Wilson with 18 minutes left in the game, if each half is 40 minutes long To determine how long did Logan play during the second half, the following calculation must be performed:

Second Half Total - Time Played by Wilson = Time Played by Logan

40 - 18 = X

22 = X

Therefore, Logan played for 22 minutes during the second half.

6 0
2 years ago
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