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Mkey [24]
3 years ago
12

Find the density of a 40 gram pyramid with rectangular base 5 x 6 cm and height 8 cm.

Mathematics
2 answers:
Vitek1552 [10]3 years ago
8 0
Density is mass/volume or g/cm^3 in this case
vpyramid=(1/3)lwh
given
l=6
w=5
h=8
V=(1/3)6*5*8
V=2*40
V=80cm^3

mass=40g

density=40g/80cm^3=0.5g/cm^3
0.5 grams per cm^3 is the density
e-lub [12.9K]3 years ago
3 0
Density is <u>mass</u>
                volume
With those dimensions, the volume of the pyramid is;
V = lw(h/3)
V = (5)(6)(8/3)
V = 80 cm^3

D = <u>   40 g    </u> = 1 g/cm^3
       80 cm^3
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Is 1/4 greater or less than 8/10
Romashka-Z-Leto [24]
1/4 is less than 8/10
8 0
3 years ago
Dante bought a new graduated cylinder for his chemistry class. It holds 1,345.6 milliliters of liquid. If the cylinder has a rad
pentagon [3]
The formula for a cylinder's volume  is
V = π r² h
V = 1345.6
π = 3.14
r = 5.8 cm

1345.6 = 3.14 * 5.8^2 h Multiply 3.14 and 5.8^2 together.
1345.6 = 105.6 h  Divide by 105.6
1345.6 / 105.6 = h
h = 12.73 cm <<<< answer.
 I don't see anything wrong with what I've done but I don't see the answer anywhere. Estimating 1345 can be rounded to 1300. 
pi * 5.8^2 = 3 * 35 = 105 which we could round to 100.

1300 / 100 about = 13 So the answer should be in the region of 100.

I cannot see any reason to believe there is an error. If there is something that has not been copied correctly, I'd like to know what it is.

 
7 0
2 years ago
What is the square root of 100?
Naily [24]
The square root of 100 is 10
6 0
2 years ago
May anyone help please
lapo4ka [179]

Depending on how flexibly you interpret "about 20 times larger" to mean, the answers are B and D.

Check the ratios of the larger number to the smaller number:

A: (2.01 x 10^7)/(4.25 x 10^6) = 2.01/4.25 x 10^1 = 20.1/4.25 = 4.729

B: (8.21 x 10^-3)/(4.13 x 10^-4) = 8.21/4.13 x 10^1 = 82.1/4.13 = 19.879

C: (4.91 x 10^6)/(5.09 x 10^3) = 4.91/5.09 x 10^3 = 4910/5.09 = 964.637

D: (5.97 x 10^4)/(3.12 x 10^3) = 5.97/3.12 x 10^1 = 59.7/3.12 = 19.135

4 0
3 years ago
Question is in photo.<br> Thanks
lana66690 [7]

Answer:

what do you mean for this question. What do you need help on?

7 0
3 years ago
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