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Mkey [24]
3 years ago
12

Find the density of a 40 gram pyramid with rectangular base 5 x 6 cm and height 8 cm.

Mathematics
2 answers:
Vitek1552 [10]3 years ago
8 0
Density is mass/volume or g/cm^3 in this case
vpyramid=(1/3)lwh
given
l=6
w=5
h=8
V=(1/3)6*5*8
V=2*40
V=80cm^3

mass=40g

density=40g/80cm^3=0.5g/cm^3
0.5 grams per cm^3 is the density
e-lub [12.9K]3 years ago
3 0
Density is <u>mass</u>
                volume
With those dimensions, the volume of the pyramid is;
V = lw(h/3)
V = (5)(6)(8/3)
V = 80 cm^3

D = <u>   40 g    </u> = 1 g/cm^3
       80 cm^3
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7 0
3 years ago
Identify the parent function that can be used to graph the function f(x)=-9(x+5)^2
svetoff [14.1K]

Answer:

Option a) f(x)=x^2

Step-by-step explanation:

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3 years ago
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AVprozaik [17]

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*please make sure to double check for yourself or get another person to look it over just incase*

8 0
2 years ago
After a dreary day of rain, the sun peeks through the clouds and a rainbow forms. You notice the rainbow is the shape of a parab
Gekata [30.6K]

We can answer the first part of the question not taking intersecting function into account. The domain of y=-x^{2}+36 is all the numbers, x∈(-∞, +∞) and the range is y∈(-∞, 36]. We can observe these results with the help of a graph, as well. Since we are talking about the rainbow, the values above the ground level will make sense. In this case, we will take into account the range as it changes between 0 and 36, included and the domain between -6 and 6. Here (0;36) is the y-intercept and (-6;0) and (6;0) are the x-intercepts of the parabola.


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The system of equations with linear and quadratic functions has got two solutions and we can observe that result from the graph. The solutions are (-5.823; 2.088) and (5.323; 7.662). The solutions are the intersection points.

7 0
3 years ago
An article suggested that yield strength (ksi) for A36 grade steel is normally distributed with μ = 44 and σ = 5.0. (a) What is
aalyn [17]

Answer:

Step-by-step explanation:

Using normal distribution,

z = (x - μ)/σ

μ= mean = 44 and

σ = standard deviation= 5.0

a) The probability that yield strength is at most 40=

P( x lesser than or equal to 40)

z = (40-44)/5= -0.8

Looking at the normal distribution table,

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Looking at the normal distribution table,

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= 0.00016

c)P( 42 lesser than or equal to x lesser than or equal to 62)

= P(x lesser than or equal to 62) - P( x lesser than or equal to 40)

= 0.99987-0.2119= 0.78797

d) What yield strength value separates the strongest 75% from the others.

To get x for strongest 75, we get the z value corresponding to 0.75 from the table

z = 0.675= (x-44)/5

x = 3.375+44 = 47.375

The rest is 25% = 0.25

we get the z value corresponding to 0.25 from the table)

z = -0.67 = (x-44)/5

-3.35= x -44

x = -44+3.35= 40.65

yield strength value that separates the strongest 75% from the others

=47.375-40.65= 6.725

3 0
3 years ago
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