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notsponge [240]
3 years ago
9

A value of at least -3

Mathematics
1 answer:
spayn [35]3 years ago
5 0

Answer:

Step-by-step explanation:

ee aya hned ttrfβΔΘΘΔΛζΞεμΘνΔμΘΞ-scjjsh¢₫₠₭₤₳₢₩₢₰៛₫₠

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Simplify the expression by combining like terms.<br> 7.2(x + 3) + 4(x - 3)
siniylev [52]

Answer: 11.2x -9.6

Step-by-step explanation:

7.2(x + 3) + 4(x - 3) -  12       - 7.2* (x + 3) + + 4*(x - 3) then

7.2x + 21.6 + 4x -  12  - Combining like terms 7.2x+ 4x  and numbers + 21.6-  12          

7.2x + 4x +21.6 -12       Then we have

11.2x -9.6

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3 years ago
Find the product of (3x+2)(3x+7)
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Answer:

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Step-by-step explanation:

3x(3x+7) +2(3x+7)

9x square +21x +6x+14

= 9x square +27x +14

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Read 2 more answers
Suppose that the functions q and r are defined as follows.
satela [25.4K]

Answer:

(r o g)(2) = 4

(q o r)(2) = 14

Step-by-step explanation:

Given

g(x) = x^2 + 5

r(x) = \sqrt{x + 7}

Solving (a): (r o q)(2)

In function:

(r o g)(x) = r(g(x))

So, first we calculate g(2)

g(x) = x^2 + 5

g(2) = 2^2 + 5

g(2) = 4 + 5

g(2) = 9

Next, we calculate r(g(2))

Substitute 9 for g(2)in r(g(2))

r(q(2)) = r(9)

This gives:

r(x) = \sqrt{x + 7}

r(9) = \sqrt{9 +7{

r(9) = \sqrt{16}{

r(9) = 4

Hence:

(r o g)(2) = 4

Solving (b): (q o r)(2)

So, first we calculate r(2)

r(x) = \sqrt{x + 7}

r(2) = \sqrt{2 + 7}

r(2) = \sqrt{9}

r(2) = 3

Next, we calculate g(r(2))

Substitute 3 for r(2)in g(r(2))

g(r(2)) = g(3)

g(x) = x^2 + 5

g(3) = 3^2 + 5

g(3) = 9 + 5

g(3) = 14

Hence:

(q o r)(2) = 14

8 0
2 years ago
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