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Olegator [25]
3 years ago
12

(01.01 LC)A dancer took forward and backward steps of equal length during a dance. After taking 16 steps total, she was back at

her starting position. How many steps did the dancer take in the forward and backward directions?
Mathematics
2 answers:
Doss [256]3 years ago
8 0

Note that the steps in total are 16. She takes the same amount of steps forward and backward, and so divide 16 by 2

16/2 = 8

She takes 8 steps forward, and 8 steps backward.

hope this helps

Gennadij [26K]3 years ago
5 0

Since the steps are the same size, and she ended up where she started, she must have taken the same number of steps forward as she took backward.

16/2 = 8

She took 8 steps forward and 8 steps backward.

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Answer:

1) y = 2x + 1

y = x + 2 Corresponding with the third graph

2) y = 3x

y = x + 3 Corresponds with the first graph

3) y = 2x - 2

y = x - 2

4) y = 2x + 3

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Likely correspond with the fourth graph

5) y = 4x + 2

y = 2x + 2 Corresponding with the second equation

Step-by-step explanation:

The groups of equation are;

1) y = 2x + 1

y = x + 2

The y-intercept of equation (1) = 1

The x-intercept of equation (1) = -1/2

The slope of equation (1) = 2

So at x = 0 y = 1 and at  y = 0 x = -1/2 and at x = 2 y  = 3

Corresponding with the third graph

The same can be shown with the second equation

2) y = 3x

y = x + 3

The y-intercept of equation (1) = 0

The x-intercept of equation (1) = 0

The slope of equation (1) = 3

So at x = 0 y = 0 and at   x = 2 y  = 6

Corresponds with the first graph

The same can be shown with the second equation

3) y = 2x - 2

y = x - 2

4) y = 2x + 3

y = x + 5

Likely correspond with the fourth graph

5) y = 4x + 2

y = 3x + 2

The y-intercept of equation (1) = 2

The x-intercept of equation (1) = -1/2

The slope of equation (1) = 4

So at x = 0 y = 2 and at  y = 0 x = -1/2 and at x = 0.5 y  =  4

Corresponding with the second equation

The same can be shown with the second equation

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$0.59 times 2= $1.18
$1.18-$0.96=$0.22
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