Answer:
d
Step-by-step explanation:
Answer
a. True
Step-by-step explanation:
Based on this survey we estimate that about 
of the college students smokes. And a 
confidence interval is ![[15.1\% ; 21.6\%]](https://tex.z-dn.net/?f=%5B15.1%5C%25%20%3B%2021.6%5C%25%5D)
. So we know that 
our estimative for the smoking rate is in the confidence interval with certainty. We also know the estimative for the smoking rate in the general population is 
. So we can write the two possible hypothesis:
Smoking rate is equal to .
Smoking rate is not equal to .
We will reject the null hypothesis 
if the estimate doesn't fall into the confidence interval for the college students smoking rate.
Since this condition holds we reject the null hypothesis. So with certainty we say that the smoking rate for the general population is different than the smoking rate for the college students.
Your answer is 94/15
if mixed, it’s 6 4/15
Here's how one would solve it:
17 + 3x2 = 6x
17 + 6 = 6x
23 = 6x
x = 23/6
There's only one solution.
Solving for the missing term and the missing coefficient (6a − )5a = ( ) a^2 − 35a
Let the missing term be X
Let the missing coefficient be Y
Therefore, (6a – X)5a = Y(a^2) – 35a
6a x 5a – X.5a = Y.a^2 – 35a
30a^2 – X.5a = Y.a^2 – 35a
Equating co-efficients,
30a^2 = Y.a^2; X.5a = 35a
30 = Y; 5X = 35
Y = 30; X = 7
Therefore, (6a-7)5a = 30 a^2 – 35a
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