All categories

3 years ago

GO.o has 3 orange picks for every 2 green. If there are 25 picks in all, how many picks are orange?

Mathematics

2 answers:

dsp733 years ago

5 0

15 oranges are picked

Reika [66]3 years ago

4 0

Given

GO.o has 3 orange picks for every 2 green

there are 25 picks in all

Find out how many picks are orange.

To proof

As given in question

GO.o has 3 orange picks for every 2 green

i.e the ratio of orange to every green becomes

$\frac{Orange}{Green}:\frac{3}{2}$

total number of picks = 25

let the GO.o pick of 3 orange picks for every 2 green =x

than the equation becomes

3x + 2x = 25

5x = 25

x = 5

Than

the number of oranges = 3x

putting the value of x

= 15

the number of green = 2x

= 10

thus the 15 picks are orange.

Hence proved

You might be interested in

What is the best estimate for the answer of 47.82 + 74.31

Marysya12 [62]

Answer:

122

Step-by-step explanation:

Round the two numbers to the nearest whole number and add.

8 0

3 years ago

A race car driver won a 300 mile race with a speed of 194 miles per hour. Find the drivers time.

agasfer [191]

Time = distance / speed

time = 300/194
time = 1.546 hrs...not sure if u need that rounded...if so, then it is 1.5 hrs or 1 1/2 hrs

8 0

3 years ago

Find the length of side s. Round to the nearest tenth if needed.

Ilya [14]

Answer:

dunno

Step-by-step explanation:

4 0

3 years ago

There were 36 balloons at the beginning of the party. By the end of the party, d of them popped. Using d, write an expression fo

kap26 [50]

Answer:

b=36-d

Step-by-step explanation:

b=balloons after being popped

d=balloons popped

6 0

3 years ago

Find the angle between the given vectors to the nearest tenth of a degree. u = <-5, -4>, v = <-4, -3> (1 point)

sesenic [268]

Angle between $u = -5i-4j , v=-4i-3j$ is $x =0$ ° .

<u>Step-by-step explanation:</u>

We have , two vectors u = <-5, -4>, v = <-4, -3> or , $u = -5i-4j , v=-4i-3j$

We need to find angle between these two vectors . Let's find out:

We know that dot product of two vectors is defined as :

$u.v =|u|(|v|)cosx$ , where x is angle between u & v !

⇒ $u.v =|u|(|v|)cosx$

⇒ $cosx =\frac{u.v}{|u|(|v|)}$

Now , $u.v = (-5i-4j)(-4i-3j)$

⇒ $u.v = (-5i-4j)(-4i)-(-5i-4j)(3j)$

⇒ $u.v = 20+12$ { $i(j) = j(i) =0$ }

⇒ $u.v = 32$

Now , Modulus of any vector $r = xi+yj$ is $|r| = \sqrt{x^{2}+y^{2}}$ So ,

$|u| = \sqrt{(-5)^{2}+(-4)^{2}} = \sqrt{25+16} = \sqrt{41} \\\\|v| = \sqrt{(-4)^{2}+(-3)^{2}} = \sqrt{16+9} = \sqrt{25} = 5$

Putting all these values in equation $cosx =\frac{u.v}{|u|(|v|)}$ we get:

⇒ $cosx =\frac{32}{5(\sqrt{41})}$

⇒ $cos^{-1}(cosx) =cos^{-1}(\frac{32}{5(6.4)})$

⇒ $x =cos^{-1}(1)$ { $cos0 = 1$ }

⇒ $x =0$ °

Therefore , Angle between $u = -5i-4j , v=-4i-3j$ is $x =0$ ° .

8 0

3 years ago