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ankoles [38]
3 years ago
13

Please help hurry!!!!! This is due in a couple of minutes!!!!

Mathematics
1 answer:
kumpel [21]3 years ago
5 0

Answer:

200 in.

Step-by-step explanation:

1250/75=5000/300=50/3 simplification

50*12=600 conversion to inches

600/3=200 simplification

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Someone help me please and thank you!! ASAP :(
pantera1 [17]
<h3>Answer: Choice D) </h3>

Work Shown:

(f+g)(x) = f(x)+g(x)\\\\(f+g)(x) = \frac{x-23}{x^2+9x-36}+\frac{1}{x+12}\\\\(f+g)(x) = \frac{x-23}{(x+12)(x-3)}+\frac{1(x-3)}{(x+12)(x-3)}\\\\(f+g)(x) = \frac{x-23+1(x-3)}{(x+12)(x-3)}\\\\(f+g)(x) = \frac{x-23+x-3}{x^2+9x-36}\\\\(f+g)(x) = \frac{2x-26}{x^2+9x-36}\\\\

We must require that x \ne -12 and x \ne 3 to avoid having 0 in the denominator. This is why choice D is the answer.

3 0
3 years ago
Felicia drew the pictures at the right to show 3/8 is greater than 3/4. What was Felicia’s mistake?
Alborosie
To show equality with fractions both fractions should be converted to show their values with the same denominator then draw a picture of those fractions.

Remember that you can only compare fractions with the same denominator as is said with other operations dealing with fractions.
8 0
4 years ago
In a large statistics course, 74% of the students passed the first exam, 72% of the students pass the second exam, and 58% of th
11111nata11111 [884]

Answer:

Required probability is 0.784 .

Step-by-step explanation:

We are given that in a large statistics course, 74% of the students passed the first exam, 72% of the students pass the second exam, and 58% of the students passed both exams.

Let Probability that the students passed the first exam = P(F) = 0.74

     Probability that the students passed the second exam = P(S) = 0.72

     Probability that the students passed both exams = P(F \bigcap S) = 0.58

Now, if the student passed the first exam, probability that he passed the second exam is given by the conditional probability of P(S/F) ;

As we know that conditional probability, P(A/B) = \frac{P(A\bigcap B)}{P(B) }

Similarly, P(S/F) = \frac{P(S\bigcap F)}{P(F) } = \frac{P(F\bigcap S)}{P(F) }  {As P(F \bigcap S) is same as P(S \bigcap F) }

                          = \frac{0.58}{0.74} = 0.784

Therefore, probability that he passed the second exam is 0.784 .

5 0
3 years ago
Please solve this quadratic equation:<br>9^x-1 = 27^X-1​
nadezda [96]

Answer:

x=1

Step-by-step explanation:

if it is truly 9^(x-1)=27^(x-1), then you dont really need to use the quadratic fromula.

5 0
3 years ago
What percent is 88 of 106
Tems11 [23]
What percent is 88 of 106?

88/106

88 ÷ 106 ≈ .83
.83 × 100 = 83
83%

83% is 88 of 106. 
4 0
3 years ago
Read 2 more answers
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