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Bingel [31]
3 years ago
13

Which type of triangle will always have at least 1-fold reflectional symmetry?

Mathematics
2 answers:
telo118 [61]3 years ago
8 0

Answer: isocleles

Step-by-step explanation:

kodGreya [7K]3 years ago
8 0

Answer:

An Isosceles triangle

Step-by-step explanation:

Isosceles triangle is a type of triangle that will always have exactly 1-fold reflection symmetry.

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A hexagon has 6 sides
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What step should you do before you write an equation to solve a word problem? 20 points
ra1l [238]

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Hewo! :3

A nice trick i use for word problems is that i highlight the numbers and what they are, like: liters, kilograms, grams, etc. say this is your word probem:

Suzie made <u>30 kilograms</u> of party mix chips and <u>40 liters of punch</u> for her party, Suzie had <u>20 people at her party</u>, how much punch and party mix chips will there be when the party is over?

I highlighted what i would have highlighted if it was a real word problem.

Good luck! Hope my trick works for you too!

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3 years ago
Ms. Marvin is buying pencils for her class. she has a total of 22 students, and she wants to give each student 2 pencils. pencil
dimaraw [331]

Answer:

4

Step-by-step explanation:

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round up= 4

7 0
3 years ago
Can someone help please
icang [17]
I would say C because you multiply 3 x H then 3 x4 I think this is the right answer but I'm not so sure though Hope it helped sort of - Ashlynn
8 0
3 years ago
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What is the factorization of 3x2 – 8x + 5?
ELEN [110]

we have

3x^{2} -8x+5

Equate the expression to zero to find the roots

3x^{2} -8x+5=0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

3x^{2} -8x=-5

Factor the leading coefficient

3(x^{2} -(8x/3))=-5

Complete the square. Remember to balance the equation by adding the same constants to each side.

3(x^{2} -(8x/3)+(16/9))=-5+(16/3)

3(x^{2} -(8x/3)+(16/9))=(1/3)

Rewrite as perfect squares

3(x-(4x/3))^{2}=(1/3)

(x-(4x/3))^{2}=(1/9)

square roots both sides

(x-\frac{4}{3})=(+/-) \sqrt{\frac{1}{9}}

x=\frac{4}{3}(+/-) \frac{1}{3}

the roots are

x=\frac{4}{3}+ \frac{1}{3}=\frac{5}{3}

x=\frac{4}{3}- \frac{1}{3}=\frac{3}{3}=1

so

3x^{2} -8x+5=3(x-\frac{5}{3})(x-1)=(3x-5)(x-1)

therefore

<u>the answer is the option</u>

(3x-5)(x-1)

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