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r-ruslan [8.4K]
3 years ago
10

F(x)=x^2. What is g(x)

Mathematics
1 answer:
xxTIMURxx [149]3 years ago
4 0

Answer:

g(x) = \frac14x^2

Step-by-step explanation:

Since f(x) and g(x) share the same top at (0,0), their difference is only a scale factor, so g(x) = ax² but we need to find a.

To find it, we use the given point of g, (2,1)

So g(2) = 1

meaning that

a·2² = 1

4a = 1

a = 1/4

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Josh has a piggy bank filled with coins. The number of dimes is three times the number of nickels. The number of nickels is five
slavikrds [6]

Answer:

nickels 15 dimes 45 pennies and quarters 10

8 0
3 years ago
Sunflower produce approximately 50 seeds per flower. If one ounce of sunflower seeds contain an average of 72 seeds, how many fl
ra1l [238]

Given :

Sunflower produce approximately 50 seeds per flower.

If one ounce of sunflower seeds contain an average of 72 seeds.

To Find :

How many flowers are needed to produce 2 pounds of seeds.

Solution :

1 pound = 16 ounces .

So , 2 pound = 32 ounces .

Number of seeds in 2 pounds of seeds, n = 32×72 = 2304 .

Number of flowers are :

N=\dfrac{2304}{50}=46.08

So , approximate number of flower required are 46.

Hence, this is the required solution.

5 0
3 years ago
What is 4.345 x 10^5 in standard form?
zalisa [80]

Answer:

Choice D.)   434,500

Step-by-step explanation:

What is 4.345 x 10^5 in standard form?

4.345 x 10^5 = 4.345 *  100,000

multiply it out:

4.345 x 10^5 = 434,500

3 0
3 years ago
The pulse rates of 174 randomly selected adult males vary from a low of 39 bpm to a high of 111 bpm. Find the minimum sample siz
Daniel [21]

Answer:

a. The sample size is approximately 97 adults

Step-by-step explanation:

The given parameters are;

The number of adults surveyed, n = 174

The lowest value of the pulse rate = 39 bpm

The highest value of the pulse rate = 111 bpm

The level of confidence used for determining the sample size = 90%

The given sample mean = 3 pm of the population mean

a. The range rule of thumb states that the standard deviation is approximately one quarter (1/4) of the range

The range = 111 bpm - 39 bpm = 72 bpm

Therefore, the standard deviation, σ = 72 bpm/4 = 18 bpm

The sample size, 'N', is given as follows;

N = \dfrac{z^2 \cdot p \cdot q}{e^2}

Where;

N = The sample size

z = The confidence level, 90% (z-score at 90% = 1.645)

p·q = σ² = 18² = 324

e² = 3² = 9

N = \dfrac{1.645^2  \times 324}{3^2} = 97.4169

Therefore the appropriate sample size, N ≈ 97 adults.

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3 years ago
I need help on this please
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She is so right Because said it bro
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