A trailer will be used to transport several 40-kilogram crates to a store. The greatest amount of weight that can be loaded onto
1 answer:
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Part 1:
Given that the length of the chord is 18 cm and the chord is midway the radius of the circle.
Thus, half the angle formed by the chord at the centre of the circle is given by:
Now,
Therefore, the radius of the circle is 10.4 cm to 1 d.p.
Part 2I:
Given that the radius of the circle is 10 cm and the length of chord AB is 8 cm. Thus, half the length of the chord is 4cm. Let the distance of the mid-point O to /AB/ be x and half the angle formed by the chord at the centre of the circle be θ, then
Now,
Part 2II:
Given that the radius of the circle is 10cm and the angle distended is 80 degrees. Let half the length of chord CD be y, then:
Thus, the length of chord CD = 2(6.428) = 12.856 which is approximately 12.9 cm.
Given that the length of the chord is 18 cm and the chord is midway the radius of the circle.
Thus, half the angle formed by the chord at the centre of the circle is given by:
Now,
Therefore, the radius of the circle is 10.4 cm to 1 d.p.
Part 2I:
Given that the radius of the circle is 10 cm and the length of chord AB is 8 cm. Thus, half the length of the chord is 4cm. Let the distance of the mid-point O to /AB/ be x and half the angle formed by the chord at the centre of the circle be θ, then
Now,
Part 2II:
Given that the radius of the circle is 10cm and the angle distended is 80 degrees. Let half the length of chord CD be y, then:
Thus, the length of chord CD = 2(6.428) = 12.856 which is approximately 12.9 cm.
<em>p = 21</em>
Step-by-step explanation:
When you have a midsegment, the base is going to be two times as large as the midsegment. You can find the midsegment if you multiply it by two and set it equal to the base. I have attached a photo below that may help you.
This is the equation we will be using.
Now let's solve! Let's start by distributing the 2 by what's in the parentheses.
Subtract p from both sides.
Add 26 to both sides.
<u>p = 21</u>
