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Ne4ueva [31]
3 years ago
12

A trailer will be used to transport several 40-kilogram crates to a store. The greatest amount of weight that can be loaded onto

the trailer is 1,050 kilograms. An 82-kilogram crate has already been loaded onto the trailer. What is the greatest number of 40-kilogram crates that can also be loaded onto the trailer?
Mathematics
1 answer:
nikklg [1K]3 years ago
5 0

Answer:

24

Step-by-step explanation:

The total capacity of the trailer is 1,050 kg.

An 82-kg crate is already loaded on the trailer.

We subtract 82 kg from 1,050 kg to find out the amount of weight still available.

1,050 kg - 82 kg = 968 kg

The trailer can still carry another 968 kg.

Each additional crate weighs 40 kg.

We divide 968 kg by 40 kg to calculate the number of crates that can still be loaded.

(968 kg)/(40 kg) = 24.2

Since we cannot place 0.2 of a crate, we round 24.2 down to 24.

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Step-by-step explanation:

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A T-shirt department store cost 7.50.the total cost in dollar of a T-shirt is givien by the function C(a)=7.5a
tigry1 [53]

Given cost function C(a) = 7.5a, where a is the number of T-shirts.

Let us complete table.

We need to plug a=1,2,3,4 in above function to get the costs to complete the table.

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In order to find the common difference we need to find the diffrences of costs 15-7.50 = 7.50

22.50-15.00=7.50.

<h3>Therefore, common difference is 7.5.</h3>

a represents the number of T-shirts.

Domain of a is the numbers we can take for a.

So, we can take value for a as 0 or greater value.

Therefore, domain for a would be a is gerater than or equal to 0.

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4 years ago
MARK AS BRAINLIEST....<br><br><br> -4-(-2)=?<br> 9-(-5)?
Flauer [41]

-2

Answer:

14

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3 years ago
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