Select the correct answer from each drop-down menu. In ΔABC, the lengths of a, b, and c are 22.5 centimeters, 18 centimeters, an
d 13.6 centimeters, respectively. m∠B = º, and m∠C = º. Round off your answers to two decimal places.
2 answers:
The complete question in the attached figure
we have that
<span>In ΔABC, the lengths of a, b, and c are 22.5 centimeters, 18 centimeters, and 13.6 centimeters
</span>we can apply the Cosine Law to find the angles of the triangle.
<span>
find angle C
c</span>²=a²+b²-2ab*cosC
cos C=(a²+b²-c²)/(2ab)--------> cos C=(22.5²+18²-13.6²)/(2*22.5*18)
<span>cos C=0.7967
C=arc cos (0.7967)-----------> C=37.19</span>°
find angle B
b²=a²+c²-2ac*cosB
cos B=(a²+c²-b²)/(2ac)--------> cos B=(22.5²+13.6²-18²)/(2*22.5*13.6)
cos B=0.60
B=arc cos (0.60)-----------> B=53.12°
<span>
the answer is
</span><span>m∠B = 53.12º
</span><span>m∠C = 37.19º</span>
we have that
<span>In ΔABC, the lengths of a, b, and c are 22.5 centimeters, 18 centimeters, and 13.6 centimeters
</span>we can apply the Cosine Law to find the angles of the triangle.
<span>
find angle C
c</span>²=a²+b²-2ab*cosC
cos C=(a²+b²-c²)/(2ab)--------> cos C=(22.5²+18²-13.6²)/(2*22.5*18)
<span>cos C=0.7967
C=arc cos (0.7967)-----------> C=37.19</span>°
find angle B
b²=a²+c²-2ac*cosB
cos B=(a²+c²-b²)/(2ac)--------> cos B=(22.5²+13.6²-18²)/(2*22.5*13.6)
cos B=0.60
B=arc cos (0.60)-----------> B=53.12°
<span>
the answer is
</span><span>m∠B = 53.12º
</span><span>m∠C = 37.19º</span>
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