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Deffense [45]
4 years ago
13

Plss help I need to show my work

Mathematics
1 answer:
Softa [21]4 years ago
4 0
<u><em>Option D suits 1/3÷3/4</em></u>
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Write a real world problem that involves a percent then model the percent used in the problem
s344n2d4d5 [400]
You go to a restaurant and your bill is $35.00. Your service was excellent so you leave a 20% tip. What was the total amount paid for the bill including the tip?

10%=$1 for every $10
15%=$1.50 for every $10
20%=2% for every $10

10% of the bill would be $3.50(move the decimal to the tens place)
15% of the bill would be $5.25( halve the 10% and add it to the original 10% tip; $3.50+$1.75)
20% of the bill would be $7.00(double the 10% tip)
7 0
4 years ago
a survey was taken of children between the ages 7 and 12. let A be the event that the person rides the bus to school, and let B
son4ous [18]

Answer:

The statement is true about whether A and B are independent eventa is fourth option:

A and B are not independent events because P(A/B)=0.375 and P(A)=0.25

Step-by-step explanation:

Let A be the event that the person rides the bus to school, then:

P(A)=75/300

P(A)=0.25

Let B be the event that the person has 3 or more siblings, then:

P(B)=24/300

P(B)=0.25


P(A/B)=9/24

P(A/B)=0.375


Like P(A/B)=0.375 is different to P(A)=0.25 the events are not independent


Answer. Fourth option:

A and B are not independent events because P(A/B)=0.375 and P(A)=0.25

3 0
3 years ago
What model describes the relationship between the amount of money in an account and time, given that the money triples every mon
Tomtit [17]
An algebraic equation that has variables for money and time
8 0
2 years ago
Dave has $15 to spend on an $8 book and two baseball cards (c) costing $2 each. for his friends. Write an inequality to show how
kenny6666 [7]
The inequality would be 15-12
4 0
3 years ago
A company did a quality check on all the packs of nuts it manufactured. Each pack of nuts is targeted to weigh 18.25 oz. A pack
IrinaVladis [17]

Answer:

x < 17.89 or x > 18.61 , since \left | x-18.25 \right |>0.36

Step-by-step explanation:

According to the question the weight is rejected if it is more than 0.36 oz, the weight should not be beyond 0.36 oz that is from the target weight of 18.25.  

We can say that, the difference between the actual weight and the target weight is greater than 0.36 oz.

Lets say the actual weight is 'x'. So,

x-18.25>0.36

But there can be times when the actual weight 'x' could be less than 0.36, So the order will be changed:

18.25-x>0.36

The absolute value will sum up these two into a single inequality:


|x-18.25|>0.36

Simplifying the inequalities, we get:

x-18.25>0.36

x>18.61   (we have added 18.25 on both sides)


 18.25-x>0.36

Subtracting 18.25 from both the sides we get:

-x>-17.89

After sign change it is:

x

So we can see that only x < 17.89 or x>18.61 since \left | x-18.25 \right |>0.36 is the one that represents the scenario given above.

5 0
4 years ago
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