Compare the areas. What is the ratio of the areas? SHOW YOUR WORK

What is the determinant of the coefficient matrix of the system 0x+0y-0z=3 0x+0y+0z=-1 0x+0y+0z=18

makvit [3.9K]

Answer:

Zero.

Step-by-step explanation:

The determinant of the coefficient matrix of the system is zero, since every coefficient is equal to zero.

3 0

3 years ago

!/8 pound of fertilizer covers 25 square feet of ground, how much fertilizer, in pounds, is needed to cover 1 square foot ground

suter [353]

Answer:

1/200 pounds

Step-by-step explanation:

Given ratio

1/8 pound ⇔ 25 square feet

To find

x ⇔ 1 square foot

Divide both sides by 25

1/8÷25 pounds ⇔ 25÷25 square feet
1/200 pounds ⇔ 1 square foot

3 0

3 years ago

Read 2 more answers

Find an equation of the line having the given slope and containing the given point. m=-7,(5,9) the equation of the line is y=

k0ka [10]

Open this web, the web is really - really helps.................................... http://www.coolmath.com/algebra/08-lines/11-finding-equation-line-point-slope-01

6 0

3 years ago

At the beginning of a snowstorm, Grayson had 10 inches of snow on his lawn. The snow then began to fall at a constant rate of 0.

maxonik [38]

Answer:

Grayson had 10 inches of snow in his lawn
the snow falls at a constant rate of 0.5 inches per hour
no snow was melting
the snow has fallen for 3 hours

Let y be the height of the snow in the lawn

Grayson had 10 inches at the beginning (at t=0) so y= 10

3 hours passed so y= 10 + 3*0.5 = 11.5 inches

Grayson had 11.5 inches after three hours

Assuming that the snow continued to fall for an unkhown time t

y = 0.5*t + 10

we had 10 at the beginning so we add 10 (+10)

the snow is growing by 0.5 inches in the single hour so we multiply by 0.5

t is the time and it can 4, 5, 6 ...... hours

Just like a function :

0.5 is the slope
t is the variable
10 is the y-intercept

3 0

3 years ago

The average yield of the standard variety off soybeans per acre on a farm in a region is 48.8 bushels per acre, with a standard

I am Lyosha [343]

Answer:

$z=\frac{53.4-48.8}{\frac{12}{\sqrt{36}}}=2.3$

$p_v =P(Z>2.3)=1-P(Z$

If we compare the p value and the significance level given $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the true mean is not significantly higher than 48.8 at 1% of signficance.

Step-by-step explanation:

1) Data given and notation

$\bar X=53.4$ represent the sample mean

$\sigma=12$ represent the population standard deviation assumed

$n=36$ sample size

$\mu_o =48.8$ represent the value that we want to test

$\alpha=0.01$ represent the significance level for the hypothesis test.

z would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

2) State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the true mean is higher than 48.8, the system of hypothesis would be:

Null hypothesis: $\mu \leq 48$

Alternative hypothesis: $\mu > 48$

Since we assume that know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

3) Calculate the statistic

We can replace in formula (1) the info given like this:

$z=\frac{53.4-48.8}{\frac{12}{\sqrt{36}}}=2.3$

4)P-value

Since is a right tailed test the p value would be:

$p_v =P(Z>2.3)=1-P(Z$

5) Conclusion

If we compare the p value and the significance level given $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the true mean is not significantly higher than 48.8 at 1% of signficance.

3 0

3 years ago