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2 years ago

How to solve this problem 0.5L/s = ml/h

Mathematics

1 answer:

vivado [14]2 years ago

5 0

Answer:

500 ml

Step-by-step explanation:

brainless????????????

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Question 15 of 43

Andrews [41]

Answer:

Option A

Step-by-step explanation:

$\frac{12}{25} \times \frac{11}{24} \times \frac{10}{23} \times \frac{9}{22}$

we start with 12 red marbles out of 25 marbles, that's the probability for the first.

in the second step we have one red marble less, wich also means one marble less overall

and so on

$\frac{12 \times 11 \times 10 \times 9}{25 \times 24 \times 23 \times 22}$

$= \frac{11880}{303600}$

can be reduced by 1320 (step by step) to

$\frac{9}{230}$

6 0

3 years ago

Help me graph this please

Whitepunk [10]

Answer:

what do you need help with

Step-by-step explanation:

5 0

3 years ago

Consider the expression 150+150(2.5). Which statements are correct?

Lemur [1.5K]

C and D

150(1+2.5) and 150(3.5)

8 0

3 years ago

Read 2 more answers

Find an equation of the line perpendicular to the graph of 28x-7y=9 that passes through the point at (4,1)

kifflom [539]

If it is perpendicular to the line 14x-7y=4, then we know our line has the opposite and inverse slope of that line. Solving for y of the first line, we get y=2x-(4/7). All we care about is the coefficient of the x term, because that will give us our slope. The slope of the first line is 2, so the slope of out line is the opposite and inverse of that slope, which -(1/2).

Plugging into our slope- point formula, where y1=(-9), x1=2, and m=(-1/2), then:

y-(-9)=(-1/2)(x-2)

y+9=(-1/2)x+1

y=(-1/2)x-8

3 0

3 years ago

Jose invested $5000 into a fund with an interest rate of 4.8%. How much interest would he earn after 2 years? A) $240 B) $24,000

pogonyaev

Answer: C) $480

Step-by-step explanation:

Given: Jose invested $5000 into a fund with an interest rate of 4.8%.

Therefore, Principal amount (P)$5000

Rate of interest = 4.8%

In decimal rate of interest(r)=0.048

Time (t)= 2 years

We know that the simple interest is given by

$S.I.=Prt\\\Rightarrow\ S.I.=5000\times0.048\times2\\\Rightarrow\ S.I.=\$480$

Hence, the interest after 2 years = $480

6 0

4 years ago