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vlada-n [284]
3 years ago
6

Calculus limit question. which one of these answers is wrong, and what is the correct answer? It's probably either d, n, or k is

n't it

Mathematics
1 answer:
stich3 [128]3 years ago
3 0

Answer:

k

Step-by-step explanation:

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Kelsey graphed the equation y = 3x + 1 as shown below.
USPshnik [31]

Answer:

D. Kelsey graphed the slope as the y-intercept and the y-intercept as the slope.

Step-by-step explanation:

The equation to graph was : y= 3x + 1 where the slope is 3 and the y-intercept is 1

However, Kelsey graph line passes through points (-3, 0)and (0, 3).From these points the equation of the line is;

m=Δy/Δx  where

m=the slope of the graph

Δy= 3-0 =3

Δx= 0--3 =3

m=3/3 = 1

The equation of the line should be;

m=Δy/Δx

1=y-3/x-0

1x= y-3

3+1x= y

y= 1x + 3 ----------where the slope is 1 and y-intercept is 3

So you can see here that in the original equation,<em> the slope m is 3 and y-intercept is 1 as shown in the first attached graph.</em>

While in the Kelsey's graph, <em>the slope is 1 and the y-intercept is 3 as in the second attached graph. </em>

<em>Thus, the correct answer is D : Kelsey graphed </em><u><em>the slope,3</em></u><em> as the </em><em>y-intercept </em><em>and the</em><u><em> y-intercept,1,</em></u><em> as the slope. </em>

Answer choice A is incorrect because Kelsey didnot graph the y-intercept, 1 on the x-axis but graphed point (-3,0) on the x-axis.

Answer choice B is incorrect because on Kelsey's equation the y-intercept is 3 and not -3. i.e. y=1x + 3

Answer choice C is incorrect because Kelsey graphed the slope as up 1 right 1 which is okay per the equation , y=1x+3.However, this incorrect because the correct graph has a slope of 3.

4 0
3 years ago
Read 2 more answers
Please help me 5-7g-3=
Archy [21]

Answer: −7g+2

If I Helped, Please Mark Me As Brainliest, Have A Great Day :D

5 0
3 years ago
Read 2 more answers
What is 6/7 Answer quickly please!!
nevsk [136]

Answer: 0.8

Step-by-step explanation:

6 0
3 years ago
Pls help fast i dont get this
IrinaVladis [17]
For the first one it is the fourth one 15/x
4 0
3 years ago
Solve for x<br>6x²+2x-12​
dem82 [27]

Answer:

Step-by-step explanation:

Solving for x means you have to factor. First factor out the GCF of 2 to get:

2(3x^2+x-6) and now we'll factor using the regular old method of ac and then factoring by grouping. In our polynomial, a = 3, b = 1, c = -6. Therefore, a times c is 3 * -6 which is -18. We need some combinations of the factors of 18 that will add to give us 1, the b term in the middle. The factors of 18 are:

1, 18

2, 9

3, 6 and that's it. Hm...it seems that won't work, so let's throw this into the quadratic formula, going back to the original and a = 6, b = 2 and c = -12:

x=\frac{-2+/-\sqrt{2^2-4(6)(-12)} }{2(6)} and

x=\frac{-2+/-\sqrt{4+288} }{12} and

x=\frac{-2+/-\sqrt{292} }{12} and

x=\frac{-2+/-\sqrt{4*73} }{12} and

x=\frac{-2+/-2\sqrt{73} }{12} which finally simplifies to

x=\frac{-1+/-\sqrt{73} }{6} No wonder that didn't factor using the traditional method of factoring! We could have found that out by finding first the value of the discriminant, but oh well!

8 0
3 years ago
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