The formula of the measurement of an exterior angle of a regular polygon is
β = 360°/n
where β = exterior angle and n = number of sides
Therefore,
n = 360°/β = 360°/18° = 20 sides
Answer:

And for the deviation we have:

And that value represent the best estimator for the population deviation since:
Step-by-step explanation:
For this case we have the following data:
1.48,1.45,1.54,1.52,1.52
The first step for this cae is find the sample mean with the following formula:

And replacing we got:

And now we can calculate the sample variance with the following formula:

And replacing we got:

And for the deviation we have:

And that value represent the best estimator for the population deviation since:
The answer is 10 i believe
Step-by-step explanation:
i hope this helps its kind of hard to see but i tried lol