Question

The quotient of the complex # below (7-2i)/(4 +3i)

Answer 1

Answer:

Step-by-step explanation:

hello :

(7-2i)/(4 +3i)

=(7-2i)×(4-3i)/(4 +3i)×(4-3i)

but : (7-2i)×(4-3i) =28-21i-8i+6i²

(7-2i)×(4-3i) = 22-29i   ....i² = -1

(4 +3i)×(4-3i) = 4²-(3i)²...(identity)

                   = 16+9 =25

so :

(7-2i)×(4-3i)/(4 +3i)×(4-3i)

=(22-29i)/25

(7-2i)/(4 +3i) = 22/25 -29/25i

(form : a+ib)