A ship sails 250km due North qnd then 150km on a bearing of 075°.1)How far North is the ship now? 2)How far East is the ship now
1 answer:
The answers to the bearing problems are listed below:
- How far North is the ship now ___________ 38.82 km
- How far East is the ship now ____________ 144.89 km
- How far is the ship from its starting point_____241.48 km
- On what bearing is it now from its original position____035°
Bearing can defined as branch of mathematics that describes the accurate location of an object at any point in time.
<h3>Analysis</h3>The answers to the problem from 1-3 can be gotten by using sin and cos to find the missing sides.
The final value can be gotten using the cosine rule
4). bearing from original position = (
+
﹣
) /
= 35°
In conclusion, the answers for each is given in the list above.
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The probability of “landing” in the shaded region to the nearest hundredth is equal to 0.79 or 79.0%.
<h3>How to determine the probability?</h3>First of all, we would determine the area of the given geometric shapes.
For the square, we have:
Mathematically, the area of a square can be calculated by using this formula;
Area = x²
Area = 50²
Area = 2500 ft².
For the circle, we have:
Mathematically, the area of a circle can be calculated by using this formula;
Area = πd²/4
Area = (3.142 × 50²)/4
Area = 1,963.75 ft².
Now, we can determine the probability as follows:
Probability = 1963.75/2500
Probability = 0.79 or 79.0%.
<h3>When the side length is 40 ft.</h3>Area = x²
Area = 40²
Area = 1600 ft².
For the circle, we have:
Area = πd²/4
Area = (3.142 × 40²)/4
Area = 1256.8 ft².
Probability = 1256.8/1600
Probability = 0.79 or 79.0%.
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