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snow_lady [41]
3 years ago
8

Work too plzthank youuuuuuuuuuu

Mathematics
1 answer:
Dovator [93]3 years ago
5 0
I would show you the picture with the work but I am on my computer because I am charging my phone.. So, I will just show the work 

15% = \frac{15}{100} =  \frac{30}{100} which gives you the whole quality of the number of 200

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Solve 2cos^2x+3cosx-2=0
solmaris [256]
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[2cos(x)~~-~~1][cos(x)~~+~~2]=0\\\\
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2cos(x)-1=0\implies 2cos(x)=1\implies cos(x)=\cfrac{1}{2}
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\measuredangle x=cos^{-1}\left( \frac{1}{2} \right)\implies \measuredangle x=
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cos(x)+2=0\implies cos(x)=-2

now, for the second case, recall that the cosine is always a value between -1 and 1, so a -2 is just a way to say, such angle doesn't exist.
8 0
3 years ago
Which table corresponds to the graph of the function below?
sweet-ann [11.9K]
B corresponds to the graph.
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3 years ago
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Find the absolute minimum and absolute maximum values of f on the given interval. f(t) = t 25 − t2 , [−1, 5]
Zina [86]

Answer: Absolute minimum: f(-1) = -2\sqrt{6}

              Absolute maximum: f(\sqrt{12.5}) = 12.5

Step-by-step explanation: To determine minimum and maximum values in a function, take the first derivative of it and then calculate the points this new function equals 0:

f(t) = t\sqrt{25-t^{2}}

f'(t) = 1.\sqrt{25-t^{2}}+\frac{t}{2}.(25-t^{2})^{-1/2}(-2t)

f'(t) = \sqrt{25-t^{2}} -\frac{t^{2}}{\sqrt{25-t^{2}} }

f'(t) = \frac{25-2t^{2}}{\sqrt{25-t^{2}} } = 0

For this function to be zero, only denominator must be zero:

25-2t^{2} = 0

t = ±\sqrt{2.5}

\sqrt{25-t^{2}} ≠ 0

t = ± 5

Now, evaluate critical points in the given interval.

t = -\sqrt{2.5} and t = - 5 don't exist in the given interval, so their f(x) don't count.

f(t) = t\sqrt{25-t^{2}}

f(-1) = -1\sqrt{25-(-1)^{2}}

f(-1) = -\sqrt{24}

f(-1) = -2\sqrt{6}

f(\sqrt{12.5}) = \sqrt{12.5} \sqrt{25-(\sqrt{12.5} )^{2}}

f(\sqrt{12.5}) = 12.5

f(5) = 5\sqrt{25-5^{2}}

f(5) = 0

Therefore, absolute maximum is f(\sqrt{12.5}) = 12.5 and absolute minimum is

f(-1) = -2\sqrt{6}.

8 0
3 years ago
Given the function<br> Calculate the following values:<br> f( - 1) =<br> f(0)<br> f(2)=
Alecsey [184]

-1 is less than 0, so you use the first equation:

3(-1) +2 = -3+2 = -1

f(-1) = -1

For 0 use the 2nd equation:

3(0) + 4 = 0+4 = 4

f(0) = 4

For 2 use the 2nd equation:

3(2) + 4 = 6+4 = 10

f(2) = 10

6 0
3 years ago
ABC is to be reflected across line M to create triangle ABC which best describes the location of B
lara31 [8.8K]
Is there an image showing the line?
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4 years ago
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