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notka56 [123]
3 years ago
15

While eating lunch Cary notices that 16 students in her class chose to eat a hot dog, while 12 students in her class chose to ea

t a hamburger. What is the ratio of students who chose to eat a hot dog to those who chose to eat a hamburger?
i need this answer please
Mathematics
2 answers:
Evgen [1.6K]3 years ago
4 0

9514 1404 393

Answer:

  4 : 3

Step-by-step explanation:

The ratio of numbers of students is ...

  hot dog : hamburger = 16 : 12 = 4 : 3

__

To reduce the ratio to lowest terms, remove the common factor of 4 from each number. 16 = 4·4; 12 = 4·3.

Stella [2.4K]3 years ago
3 0

Answer:

The \: ratio \: is \: \: 4 :  3 \:i .e \:  \frac{4}{3}

Step-by-step explanation:

number \: of \: students  \: who  \: chose \: \\   to \:  eat  \: a \:  hot  \: dog  \: is \: 16. \\ number \: of \: students  \: who  \: chose \: \\   to \:  eat  \: a \:  hamburger  \: is \: 12. \\

the \: ratio \: is \: number \: of \: students  \: who  \: chose \: \\   to \:  eat  \: a \:  hot  \: dog  \: \div \\ number \: of \: students  \: who  \: chose \: \\   to \:  eat  \: a \:  hamburger  \\ so \: the \: ratio \:is  \:  \frac{16}{12}  =  \frac{4}{3}

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Select the correct answer. Which expression is equivalent to 8x^2^3 sqrt 375x + 2^3 sqrt 3x^7, if x=0?
natima [27]

Answer:

(8x^3)^ \frac{2}{3} \sqrt{75x^3}  + 2^3 \sqrt{ 3x^7} =28x^3\sqrt{3x}

Step-by-step explanation:

The question is poorly formatted. The original question is:

(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7

We have:

(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7

Open bracket

(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7} =(8^ \frac{2}{3} *x^{3* \frac{2}{3}}) \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}

(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7} =(8^ \frac{2}{3} *x^2) \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}

Express 8 as 2^3

(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7} =(2^{3* \frac{2}{3}} *x^2) \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}

(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7} =(2^2 *x^2) \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}

(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7} =4x^2 \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}

Express 2^3 as 8

(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}=4x^2 \sqrt{75x^3} + 8\sqrt{ 3x^7}

Expand each exponent

(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}=4x^2 \sqrt{25x^2 *3x} + 8\sqrt{ 3x * x^6}

Split

(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}=4x^2 \sqrt{25x^2} *\sqrt{3x} + 8\sqrt{3x} * \sqrt{x^6}

(8x^3)^ \frac{2}{3} \sqrt{75x^3}  + 2^3 \sqrt{ 3x^7} =4x^2 *5x *\sqrt{3x} + 8\sqrt{3x} * x^3

(8x^3)^ \frac{2}{3} \sqrt{75x^3}  + 2^3 \sqrt{ 3x^7} =20x^3\sqrt{3x} + 8x^3\sqrt{3x}

Factorize

(8x^3)^ \frac{2}{3} \sqrt{75x^3}  + 2^3 \sqrt{ 3x^7} =28x^3\sqrt{3x}

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Ivahew [28]

Problem 1

x = some unknown number

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2(3x-7) = two times the difference of three times a number and seven

2(3x-7) = x

The last equation is formed because the expression we built up is equal to the original number in question

<h3>Answer:  2(3x-7) = x</h3>

===========================================================

Problem 2

Use the distribution rule to get

3(2x+4)-2x

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From here, we combine like terms. That means we combine the 6x and -2x to get 4x

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How did she get 16x? Possibly because she mistakenly thought she could add 4x to 12 to get 16x. This only works if the 12 had x attached to it.

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Problem 3

L = length = horizontal dimension = (d+15) ft

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P = perimeter of the rectangle = 108 ft

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108 = 2(d+15+d-3)

108 = 2(2d+12)

108 = 4d+24

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4d = 108-24

4d = 84

d = 84/4

d = 21

The deep end is 21 feet long.

This means the overall horizontal length is d+15 = 21+15 = 36 feet and the the vertical width is d-3 = 21-3 = 18 feet

The overall dimensions of the rectangular pool are 36 ft by 18 ft

<h3>Answer:  d = 21</h3>
7 0
3 years ago
What is 7/9 divided by 1/3
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Answer:

\frac{21}{9}

Step-by-step explanation:

\frac{7}{9} (divide)\frac{1}{3} = \frac{7}{9}*\frac{3}{1} = \frac{21}{9}

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erastovalidia [21]

Answer:

120°

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