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marin [14]
3 years ago
15

I am both unicellular and multicellular depending on how old I am. When I am getting ready to reproduce, my cells join together

to make a slippery, slithering mass that is bright orange. When mature, I dry out and release millions of spores. I eat by digesting dead leaves and absorbing the nutrients.
What kingdom do I belong in?
Biology
1 answer:
labwork [276]3 years ago
6 0

Answer:

Kingdom Protista.

Explanation:

This is a perfect behaviour of a slime mold which is known to be of the kingdom protista. Slime molds are usually found in lawns, and on the forest floor, deciduous logs and soil too.

  Protists are made up of eucaryotic cells in which the cell structure is complex with a well defined nucleus. Some of them move around with their flagella or by forming pseudopodia also known as their false sheet.

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Nitrogen waste is the byproduct of _______ metabolism
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Answer:

Protein

EXPLANATION:

All of these substances are produced from protein metabolism.

8 0
3 years ago
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Practice 3: Which of these statements about fungi are true? Select all that apply.
yanalaym [24]

Answer:

B

Explanation:

Fungal spores (macro- and microconidia) are inhaled and develop into yeast in the lung parenchyma.

8 0
3 years ago
WILL MARK BRAINLEST. Punnett squares use mathematical probability to help predict the genotype and phenotype combinations in gen
Y_Kistochka [10]
I believe it is C :)
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3 years ago
Enzymes speed up a biological reactions by______
kari74 [83]
Enzymes speed up a biological reactions by lowering the activation energy. 

Hope it helped you, and have a great day!

-Charlie 

Thank you so much!!!!!!!!
6 0
3 years ago
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22. A plant geneticist is investigating the inheritance of genes for bitter taste (Su) and explosive rind (e) in watermelon (Cit
mylen [45]

Answer:

See the answer below

Explanation:

Using the formula for calculating Chi square (X^2):

X^2  =  \frac{(O - E)^2}{E} where O = observed frequency and E = expected frequency.

The observed frequencies for the four phenotypes are 88, 62, 62, and 81 respectively.

For the expected frequency, the phenotypes are supposed to assort in 9:3:3:1 according to Mendel ratio.

Hence, expected frequencies are calculated as:

phenotype (1) = 9/16 x 293 = 164.81

phenotype (2) = 3/16 x 293 = 54.94

phenotype (3) = 3/16 x 293 = 54.94

phenotype (4) = 1/16 x 293 = 18.31

The X^2 is calculated thus:

Phenotype            O               E                             X^2

  1                          88            164.81            \frac{(88 - 164.81)^2}{164.81} = 35.80

  2                          62             54.94            \frac{(62 - 54.94)^2}{54.94} = 0.91

  3                           62             54.94              \frac{(62 - 54.94)^2}{54.94} = 0.91

  4                            81              18.31               \frac{(81 - 18.31)^2}{18.31} = 214.64

Total X^2 = 35.80 + 0.91 + 0.91 + 214.64 = 252.26

To the nearest tenth = 252

Degree of freedom = n - 1 = 4- 1 = 3

X^2 tabulated  = 7.815

<em>The calculated </em>X^2<em> exceeds the critical value, hence, the null hypothesis is rejected. The two genes did not assort independently.        </em>

4 0
2 years ago
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