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Softa [21]
3 years ago
7

Which equation represents a circle with a center at (-2,-8) and a radius of 11?

Mathematics
2 answers:
andreyandreev [35.5K]3 years ago
6 0

Answer:

(x – 2)² + (y + 8)² = 121

Step-by-step explanation:

aev [14]3 years ago
3 0
The answer is B. (x-2)^2+(y+8)^2=121
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If y= 6 when x= 24, find the value of x when y= 7
Shtirlitz [24]

Answer:

x=28

Step-by-step explanation:

the y to x ratio is 1:4 or in other words all you need to do is multiply the y by 4 to get your new x value

-Hope this helps

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3 years ago
Read 2 more answers
Which could be the first step in simplifying this expression? Check all that apply. (x cubed x Superscript negative 6 Baseline)
PtichkaEL [24]

Answer:

(x^{-3} )^{2}

x^6 x^{-12}

Step-by-step explanation:

(x^{3} x^{-6} )^{2} is the expression given to be solved.

First of all let us have a look at <u>3 formulas</u>:

1.\ p^a \times p^b = p^{(a+b)}\\2.\ (p^a \times q^b)^c = (p^{a})^c \times (q^{b})^c\\3.\ (p^a)^b = p^{a\times b}

Both the formula can be applied to the expression((x^{3} x^{-6} )^{2}) during the first step while solving it.

<u>Applying formula (1):</u>

(x^{3} x^{-6} )^{2}

Comparing the terms of (x^{3} x^{-6} ) with p^a \times p^b

p=x, a =3, b=-6

\Rightarrow x^{3+(-6)}\\\Rightarrow x^{3-6}\\\Rightarrow x^{-3}

So, (x^{3} x^{-6} )^{2} is reduced to (x^{-3} )^{2}

<u>Applying formula (2):</u>

Comparing the terms of (x^{3} x^{-6} )^{2} with (p^a \times q^b)^c

p=q=x, a =3, b=-6, c=2

\Rightarrow (x^{3})^2\times (x^{-6})^2\\\text{Applying Formula (3)}\\x^6 x^{-12}

So, (x^{3} x^{-6} )^{2} is reduced to x^6 x^{-12}.

So, the answers can be:

(x^{-3} )^{2}

x^6 x^{-12}

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At the bottom!!

Step-by-step explanation:

y=2

2=0+x

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