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GalinKa [24]
3 years ago
6

I have 2 questions

Mathematics
1 answer:
ivann1987 [24]3 years ago
8 0
When given a literal equation, you will often be asked to solve the equation for a given variable. The goal is to isolate that given variable. The process is the same process that you use to solve linear equations; the only difference is that you will be working with a lot more letters, and you may not be able to simplify as much as you can with linear equations.

2: x = -5/3 ; y = -4/3 (-5/3, -4/3)
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The answer is 47. Just keep adding 4.

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11. In another country, a road sign reads "80
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B because I don’t even know lol
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a group sold 150 flowers and trees. they sold the flowers for $3.00 each and the trees for $2.00 each.​
Gwar [14]

Answer: incomplete question

Complete question:A group sold 150 flowers and trees. They sold the flowers for $3.00 each and the trees for $2.00 each. They made $300.00 from this sale.

Which equation will help to determine the number of flowers and the number of trees sold?

A. 2F + 3T = 150

B. F + T = 300

C. 3F + 2T = 300

D. F + T = 150 + 300

Answer: C. 3F + 2T = 300

Step-by-step explanation:

Let F stand for flower and T for trees

Flowers sold for $3 and trees sold for $2

Therefore, F + T = 150. . .1

3F + 2T = $300. . .2

Equation 2 would help determine the cost of selling tree.

3F+2T=$300

4 0
4 years ago
A jar contains 49 marbles, of which 18 are blue, 2 are red, and the rest are green. What is the ratio of green marbles to all ma
siniylev [52]

Answer:

20:19

Step-by-step explanation:

5 0
4 years ago
Read 2 more answers
Two cities are building bicycle paths. Charles City has built 5km of bicycle paths by the end of the first month, and the total
sergey [27]

Answer:

Month 4

Step-by-step explanation:

To solve this problem we must propose an equation that models the number of kilometers of bicycle trails made monthly in Charles City and in Tinsel Town

<em>For Charles City </em>we know that the number of kilometers built in the first month is 5, and it doubles every month. Then we have an exponential equation, in base 2, whose initial value is 5.

This equation has the following form:

y = C_1 (2^{x-1})

Where:

C_1 is the number of kilometers built in month 1

x is the number of months: {1, 2, 3, 4, 5 ... x}

x = 1 represents month 1.

So:

Charles\ City\ (km) = 5(2^{x-1})

<em>For Tinsel Town</em> we know that the number of kilometers built in the first month is 21 and increases at a fixed rate of 5 kilometers per month. This can be modeled by a linear equation.

Tinsel\ Town\ (km) = 21 + 5(x-1)

Where x is the number of months. x: {1, 2, 3, 4, 5 ...}

We want to know at the end of what month the total length of the cycle lanes in Charles City first exceeds the length in Tinsel Town

Then we equal both equations and clear x.

5 (2^{x-1}) = 21 + 5(x-1)\\\\5 (2^{x-1}) - (21 + 5(x-1)) = 0

Clearing x from this equation is very difficult, so to find x, we iterate until we get the value of x that causes the equation to approach 0.

For x = 3

5(2^{3-1}) - (21 +5(3-1)) = 0\\\\20- 31= -11

For x = 4

5(2^{4-1}) - (21 +5(4-1)) = 0\\\\40 - 36 = 4

<em>The value must be between x = 3 and x = 4</em>

For x = 3.8

5 (2^{3.8-1}) - (21 +5(3.8-1)) = 0\\\\34.82 - 35 = 0.18

Then x ≈ 3.8 months.

Finally we have that By the end of the fourth month the total length of the cycle lanes in Charles City exceeds the length in Tinsel Town

6 0
4 years ago
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