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GalinKa [24]
3 years ago
6

I have 2 questions

Mathematics
1 answer:
ivann1987 [24]3 years ago
8 0
When given a literal equation, you will often be asked to solve the equation for a given variable. The goal is to isolate that given variable. The process is the same process that you use to solve linear equations; the only difference is that you will be working with a lot more letters, and you may not be able to simplify as much as you can with linear equations.

2: x = -5/3 ; y = -4/3 (-5/3, -4/3)
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Need help, thanks in advance. Will mark brainliest
Sergeu [11.5K]

The length of side x is a, .6

5 0
3 years ago
Solve 9x-7y=-7 i don't know how to do it so could you show me step by step please
Lesechka [4]

First of all, you need to know what a 'solution' is, so you'll know it
when you see it.

A 'solution' to an equation is a number, or a set of numbers, that
you can write in place of the variables (the letters), and when you
do that, the equation will have only numbers in it, and it'll be a true
statement.

Your equation has two variables in it ... 'x' and 'y' .  In order to find
just a single set of numbers for what both of them must be, you
would need two equations.

The way it stands now, with only one equation, there are actually
an infinite number of solutions.  Each solution is a pair of numbers ...
one for 'x' and one for 'y' ... and if you write them into the equation
in place of 'x' and 'y', then the equation is a true statement. 
I'll show you how to tell if a pair of numbers is a solution or not.

Here's what that looks like:

Say I give you two pairs of numbers, and I tell you that both of them
are solutions to your equation.  The 'solutions' I give you are

          x=0
          y=1
and
          x=2
          y=3 .

You don't trust me, and you say to me "Wait just a minute there, dude ! 
Not so fast.  I'll need to check them out and see if those are really solutions
to my equation."

You take the first pair and write it into your equation:
x=1, y=0
                                   9x  -  7y  = -7
                                  9(0) - 7(1) = -7
                                   0    -  7   = -7
                                           -7   = -7
OK.  That's a true statement.
So x=0, y=1 is a solution.

Now check the other one I gave you:
x=2, y=3
                                   9x  -  7y  = -7
                                  9(2) - 7(3) = -7
                                   18  -  21  = -7
                                        -3      = -7
This is NOT a true statement.
So  x=2, y=3 is NOT a solution to your equation.
I pulled a fast one on you.  If I was charging you money for solutions,
then you would not pay me for this one, because it's not a solution.

8 0
3 years ago
Kayla drives 15 miles in 20 minutes. If she drove one hour in total at the same rat how far did she go? Before you try that prob
alisha [4.7K]

Answer:

Kayla drove 45miles

5 0
3 years ago
Read 2 more answers
The mean points obtained in an aptitude examination is 159 points with a standard deviation of 13 points. What is the probabilit
Korolek [52]

Answer:

0.4514 = 45.14% probability that the mean of the sample would differ from the population mean by less than 1 point if 60 exams are sampled

Step-by-step explanation:

To solve this question, we have to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 159, \sigma = 13, n = 60, s = \frac{13}{\sqrt{60}} = 1.68

What is the probability that the mean of the sample would differ from the population mean by less than 1 point if 60 exams are sampled?

This is the pvalue of Z when X = 159+1 = 160 subtracted by the pvalue of Z when X = 159-1 = 158. So

X = 160

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{160 - 159}{1.68}

Z = 0.6

Z = 0.6 has a pvalue of 0.7257

X = 150

Z = \frac{X - \mu}{s}

Z = \frac{158 - 159}{1.68}

Z = -0.6

Z = -0.6 has a pvalue of 0.2743

0.7257 - 0.2743 = 0.4514

0.4514 = 45.14% probability that the mean of the sample would differ from the population mean by less than 1 point if 60 exams are sampled

7 0
3 years ago
Convert the polar expression of this complex number into its rectangular form:
Sergio [31]

Answer:MARK BRAINLLEST MARK BRAINLLEST

(−5/2, 5/2√3)

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Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
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