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3 years ago

11

A stage designer is making a rectangular drape that is 7 yards in length and 16 yards in width. The fabric for the drape cost $2

.90 per square yard. How much will it cost to make the drape?

1 answer:

USPshnik [31]3 years ago

6 0

Yard to square yard
example: 1yard*1 = 1square yard so 6*6=36 square yards. 7*7=42
36*2.90=104.40
42*2.90=121.8
104.40+121.8=$226.20

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Please help me with this

larisa [96]

Answer:

1936

Step-by-step explanation:

diameter = 44ft

radius = d/2 = 22ft

SA=4π22²

SA=4π(484)

SA=1936π ft

7 0

3 years ago

Find two functions f(x) and g(x) such that h(x) = ( f∘ g)(x) , if h(x) = √ + 5

marta [7]

If we know that h(x) = (f ° g) (x) = √x + 5, then f(x) = x + 5 and g(x) = √x by applying the <em>binary</em> operation of composition between two functions.

<h3>How to find the two functions behind a composed function</h3>

Let be f and g two functions, h is a composition of f with respect to g when the <em>input</em> variable of f is equal to g. The <em>composed</em> function is h(x) = √x + 5 and there may be more than a solution. One of these solutions are f(x) = x + 5 and g(x) = √x.

If we know that h(x) = (f ° g) (x) = √x + 5, then f(x) = x + 5 and g(x) = √x by applying the <em>binary</em> operation of composition between two functions.

To learn more on composed functions: brainly.com/question/12158468

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3 0

2 years ago

Fill in the blank Please help me this is due 6pm !!! I will give brainliest

ruslelena [56]

Answer:

64 degrees

Step-by-step explanation:

tan\theta =3/4

this equals 0.6435011 x 100 = 64.35011

pls mark brainliest .....:)

7 0

3 years ago

Titus works at a hotel. Part of his job is to keep the complimentary pitcher of water at least half full and always with ice. Wh

RoseWind [281]

Answer:

Answer:

t ≥ 158.33, or rounded, t ≥ <u><em>160</em></u>

Given:

W –0.414t + 129.549

W = levels

T = # minutes

Find:

how many minutes would the water level be less than or equal to 64 cups?

Steps:

<u>set up the equation</u>

-0.414t + 129.549 ≤ 64

<u>first subtract from both sides to isolate 't'</u>

-0.414t + 129.549 - 129.549 ≤ 64 - 129.549

-0.414t ≤ -65.549

<u>divide both sides by -0.414:</u>

-0.414t/-0.414 ≤ -65.549/-0.414

<u><em>t ≥ 158.33</em></u>

8 0

2 years ago

Assume that a sample is used to estimate a population proportion p. Find the 99% confidence interval for a sample of size 229 wi

meriva

Answer:

A. 99% CI for p: 0.125 < p < 0.259

B. 99% CI for p: 0.807 < p < 0.911

C. 95% CI for p: 0.776 < p < 0.844

D. 95% CI using t-distribution: 23.7 < µ < 40.3

Step-by-step explanation:

A.

$p=\frac{x}{n} =\frac{44}{229} = 0.192139738$

Confidence = 99% = 0.99

$\alpha$ =1 - confidence = 1 - 0.99 = 0.01

Critical z-value = $z_{\alpha/2}=z_{0.01/2}=z_{0.005}=2.58$ (from z-table)

SE = Standard Error of p

$SE=\sqrt{\frac{p(1-p)}{n} }$

$SE=\sqrt{\frac{0.192139738(1-0.192139738)}{229} }$

$SE=\sqrt{\frac{0.155222059}{229} }$

SE = 0.026035

E = Margin of Error

E = z-value * SE = 2.58 * 0.026035

E = 0.067170516

Lower Limit = p - E = 0.192139738 - 0.067170516 = 0.125

Upper Limit = p + E = 0.192139738 + 0.067170516 = 0.259

99% CI for p: 0.125 < p < 0.259

B.

$p=\frac{x}{n} =\frac{256}{298} = 0.8590604$

Confidence = 99% = 0.99

$\alpha$ =1 - confidence = 1 - 0.99 = 0.01

Critical z-value = $z_{\alpha/2}=z_{0.01/2}=z_{0.005}=2.58$ (from z-table)

SE = Standard Error of p

$SE=\sqrt{\frac{p(1-p)}{n} }$

$SE=\sqrt{\frac{0.8590604(1-0.8590604)}{298} }$

$SE=\sqrt{\frac{0.121075629}{298} }$

SE = 0.020157

E = Margin of Error

E = z-value * SE = 2.58 * 0.020157

E = 0.052004

Lower Limit = p - E = 0.8590604 - 0.052004 = 0.807

Upper Limit = p + E = 0.8590604 + 0.052004 = 0.911

99% CI for p: 0.125 < p < 0.259

C.

$p=\frac{x}{n} =\frac{405}{500} = 0.81$

Confidence = 95% = 0.95

$\alpha$ =1 - confidence = 1 - 0.95 = 0.05

Critical z-value = $z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96$ (from z-table)

SE = Standard Error of p

$SE=\sqrt{\frac{p(1-p)}{n} }$

$SE=\sqrt{\frac{0.81(1-0.81)}{500} }$

$SE=\sqrt{\frac{0.1539}{500} }$

SE = 0.017544

E = Margin of Error

E = z-value * SE = 1.96 * 0.017544

E = 0.034387

Lower Limit = p - E = 0.81 - 0.034387 = 0.776

Upper Limit = p + E = 0.81 + 0.034387 = 0.844

95% CI for p: 0.776 < p < 0.844

D.

x = sample mean = 32

s = sample standard deviation = 13

n = sample size = 12

Confidence = 95% = 0.95

$\alpha$ =1 - confidence = 1 - 0.95 = 0.05

Being the sample size less than 30, we use the statistical t.

df = degree of freedom = n - 1 = 12 - 1 = 11

Critical t-value = $t_{\alpha/2,df}=t_{0.05/2,11}=t_{0.025,11}=2.201$ (from t-table, two tails, df=11)

SE = standard error

$SE=\frac{s_{x} }{\sqrt{n} } =\frac{13 }{\sqrt{12} }=3.752777$

E = margin of error

E = t-value * SE = 2.201 * 3.752777 = 8.259862

Lower Limit = x - E = 32 - 8.259862 = 23.7

Upper Limit = x + E = 32 + 8.259862 = 40.3

95% CI using t-distribution: 23.7 < µ < 40.3

Hope this helps!

4 0

3 years ago