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Allushta [10]
3 years ago
12

Need help, thanks in advance. Will mark brainliest

Mathematics
1 answer:
Sergeu [11.5K]3 years ago
5 0

The length of side x is a, .6

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3-3x6+2= what is the right answer?
Kamila [148]
Use PEMDAS:-

3 - 3 × 6 + 2 = ?
3 - 18 + 2 = ?
-15 + 2 =
-13 

3 - 3 × 6 + 2 = -13. 
8 0
3 years ago
F(x) = x(2x/2)/x(x+5)(x+6)^2 <br><br> Find the vertical asymptotes?
Alex Ar [27]

Answer:

  x = -5, x = -6

Step-by-step explanation:

After canceling common terms from numerator and denominator, there are two factors remaining in the denominator that can become zero. The vertical asymptotes are at those values of x.

\displaystyle F(x)=\frac{x\frac{2x}{2}}{x(x+5)(x+6)}=\frac{x}{(x+5)(x+6)}

The denominator will be zero when ...

  x + 5 = 0 . . . . at x = -5

  x + 6 = 0 . . . . at x = -6

7 0
3 years ago
HOw do you find what are the x intercepts of a graph
maw [93]
Wherever the line hits on the horizontal line on a graph.
5 0
3 years ago
Read 2 more answers
Equivalent expression of 10+(x divided 16)
Ivahew [28]

Answer:

x/16 + 10

Step-by-step explanation:

10+(x÷16)

To add or subtract expressions, expand them to make their denominators the same. Multiply 10 times 16/16.

10 x 16 / 16 + x/16

Since 10 x 16 / 16 and x/16 have the same denominator, add them by adding their numerators.

10 x 16 + x / 16

Do the multiplications in 10×16+x.

160 + x / 16 = x/16 + 10

4 0
3 years ago
find the margin of error to use for this sample mean sushi based on a sample of 35 people he average out of pieces of sushi a pe
NNADVOKAT [17]

Answer:

{13.7756,18.2244}

Step-by-step explanation:

Given the sample size, the margin of error can be calculated with the formula M=Z*\frac{\sigma}{\sqrt{n}} where Z is the critical value for the desired confidence level, σ is the population standard deviation, and n is the sample size. Therefore, our margin of error for a 90% confidence level is:

M=Z*\frac{\sigma}{\sqrt{n}}=1.645*(\frac{8}{\sqrt{35}})=2.2244

The formula for a confidence interval is CI=\bar{x}+M where x-bar is the sample mean. Therefore, the 90% confidence interval for the mean amount of sushi pieces a person can eat is:

CI=\bar{x}\pm[M]=16\pm2.2244={13.7756,18.2244}

Therefore, we are 90% confident that the true mean amount of sushi pieces a person can eat is contained within the interval {13.7756,18.2244}

7 0
3 years ago
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