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docker41 [41]
3 years ago
13

Simplify 4 to the 7th over 5 squared all raised to the 3rd power.

Mathematics
1 answer:
Radda [10]3 years ago
6 0
First write out your original equation.
{(\frac{ {4}^{7} }{ {5}^{2} } ) }^{3}
Then use the law of exponents(power of a power) to simplify.
\frac{ {4}^{21} }{ {5}^{6} }
(Multiply the numerator and denominator exponents by the outside power.)

The answer is 4 to the 21st over 5 to the 6th.
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steposvetlana [31]

Answer:

Paint A: 11.2g

Paint B: 7g

Paint C: 7.1g

Step-by-step explanation:

5 and above give it a shove 4 and below let it go

5 0
3 years ago
The product of two consecutive numbers is 4 more than three times the larger. find the integer​
Stella [2.4K]

Answer:

Step-by-step explanation:

Let the first integer be x, then the next is x+1.

x(x + 1) = 3(x + 1) + 4

x^2 + x = 3x+ 3 + 4

x^2 + x - 3x - 7 = 0

x^2 - 2x - 7 = 0

Solving this does not give an integer so maybe there's something wrong with the question??

7 0
3 years ago
Mathematics probability
Gelneren [198K]

Do you have a specific question or something like that which you need answering?

6 0
3 years ago
I NEED HELP AND IM ON A TIMED TEST
stira [4]

This Question is not Complete

Complete question

The number of absences per student in each of two classes is shown on the dot plots below.

A dot plot titled Number of absences per student in Misses Anderson's class. The number line goes from 0 to 6. There is 1 dot above 0, 3 above 1, 3 above 2, 3 above 3, 1 above 4, and 0 above 5 and 6.

A dot plot titled Number of absences per student in Misses Bergot's class. The number line goes from 0 to 6. There is 1 dot above 0, 1 above 1, 2 above 2, 3 above 3, 2 above 4, 1 above 5, and 1 above 6.

Which statements accurately compare the two data sets? Select three options.

a. The mean number of absences is greater in Mrs. Anderson’s class.

b. The mean number of absences is greater in Mrs. Bergot’s class.

c. There is more variability in Mrs. Anderson’s data set.

d. There is more variability in Mrs. Bergot’s data set.

e. The mean and MAD are better representations of these data sets than the median and IQR.

Answer:

b. The mean number of absences is greater in Mrs. Bergot’s class.

d. There is more variability in Mrs. Bergot’s data set.

e. The mean and MAD are better representations of these data sets than the median and IQR.

Step-by-step explanation:

From the above data given in the question and the options given to us, we can observe from the comparison of both the number of absences in Mrs Bergot's class to that in Mrs Anderson's class, there will be a presence of variation in the data of one of the classes and that class happens to be Mrs Bergot's class.

The appropriate statistical tool that we can be used to determine and measure the centre of variability of the data is Mean and Mean Absolute Deviation.

7 0
3 years ago
Evaluate.<br> PLEASE HELP QUICK!
Alinara [238K]

Answer:

54

Step-by-step explanation:

4^3-4/2*5

4^3=64

64-4/2*5

-4/2=-2

64-2*5

-2*5=-10

64-10=54

Parenthesis

Exponent

Multiply or Divide (whichever comes first)

Add or Subtract (whichever comes first)

Hope this helps

5 0
2 years ago
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