<span>y in (-oo:+oo)
(3*y+6)/11 = -9 // + 9
(3*y+6)/11+9 = 0
(3*y+6)/11+(9*11)/11 = 0
3*y+9*11+6 = 0
3*y+105 = 0
(3*y+105)/11 = 0
(3*y+105)/11 = 0 // * 11
3*y+105 = 0
3*y+105 = 0 // - 105
3*y = -105 // : 3
y = -105/3
y = -35
y = -35</span>
9514 1404 393
Answer:
12 liters
Step-by-step explanation:
The kerosene usage is assumed to be jointly proportional to the number of stoves and the number of hours. That is ...
v = k·s·h . . . . . for s stoves running h hours
Then the value of k is ...
k = v/(sh) = (16 L)/(12·14) = 2/21 . . . . liters per stove-hour
Then the volume of kerosene required for 7 stoves and 18 hours is ...
v = (2/21)·s·h
v = (2/21)(7)(18) = 12 . . . liters
Answer:
2 + x + y
Step-by-step explanation:
Answer:
18
Step-by-step explanation:
6(7e+3)=6*7e + 6*3=42e + 18
